JAXB從xml文件檢索值的程序

Question

我試圖從使用JAXB的xml檢索值。下面詳細：

我OrderValidation.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> 
    <OrderValidation> 
     <OrderType name="Activation-Activation"> 
      <Product> 
       <Name>TV_SAT</Name> 
       <ActionCode>ADD</ActionCode> 
      </Product> 
     </OrderType> 
     <OrderType name="Change Owner-Change Owner"> 
      <Product> 
       <Name>TV_SAT_EQUIPMENT</Name> 
       <ActionCode>EXISTING</ActionCode> 
      </Product> 
     </OrderType> 
    </OrderValidation> 

這裏是我的Orderxml.java

@XmlRootElement(name ="OrderValidation") 
public class Orderxml 
{ 
    private String name; 
    private String Product; 
    private String OrderType; 

    public Orderxml() {} 
    public Orderxml(String name, String productclass, String ordertype) 
    { 
     super(); 

     this.name = name; 
     this.Product = productclass; 
     this.OrderType = ordertype; 
    } 
    @XmlAttribute 
    public String getName() 
    { 
     return name; 
    } 
    public void setName(String name) 
    { 
     this.name = name; 
    } 
    @XmlElement 
    public String getProductName() 
    { 
     return Product; 
    } 
    public void setProductName(String productclass) 
    { 
     this.Product = productclass; 
    } 
    @XmlElement 
    public String getOrderType() 
    { 
     return OrderType; 
    } 
    public void setOrderType(String ordertype) 
    { 
     this.OrderType = ordertype; 
    } 
} 

我的解組代碼（主類）

public static void main(String[] args) 
{ 
    try 
    { 
     File file = new File("C:///OrderValidation.xml"); 
     System.out.println(1); 
     JAXBContext jaxbContext = JAXBContext.newInstance(Orderxml.class); 
     System.out.println(2); 
     Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller(); 
     System.out.println(3); 
     Orderxml ord= (Orderxml) jaxbUnmarshaller.unmarshal(file); 
     System.out.println(4); 
     System.out.println(ord.getOrderType()+". "+ord.getProductName()); 
    } 
    catch (JAXBException e) 
    { 
     System.out.println("Issue is here"); 
     e.printStackTrace(); 
    } 
} 

當我執行它的代碼是拋出null作爲輸出。請向我建議代碼中的更改以檢索值。在此先感謝

Answer 1

您JAXB POJOs似乎不正確。根據您的XML結構應該是這樣的：

@XmlRootElement(name ="OrderValidation") 
public class Orderxml 
{ 
    @XmlElement("OrderType") 
    private List<OrderType> orderTypes; 
} 



public class OrderType{ 
    @XmlElement("Product") 
    private Product product; 
    @XmlAttribute(name="name") 
    private String name; 
} 


public class Product { 
    @XmlElement("Name") 
    private String name; 
    @XmlElement("ActionCode") 
    private String actionCode; 
} 

可以使用在線工具生成XML近似XSD，然後使用schemagen工具生成的POJO比手工寫它。