如何在Oracle中「打開」XML數據

Question

以下是一些我想在PL/SQL中重寫的TSQL示例。

DECLARE @xml XML 

SET @xml = '<theRange> 
    <theRow><First>Bob</First><Last>Smith</Last><Age>30</Age></theRow> 
    <theRow><First>Sue</First><Last>Jones</Last><Age>34</Age></theRow> 
    <theRow><First>John</First><Last>Bates</Last><Age>40</Age></theRow> 
</theRange>' 

;WITH OpenedXML AS (
    SELECT r.value('First[1]','varchar(50)') AS First, 
     r.value('Last[1]','varchar(50)') AS Last, 
     r.value('Age[1]','int') AS Age 
    FROM @xml.nodes('//theRange/theRow') AS Row(r) 
) 
SELECT * 
FROM OpenedXML 
WHERE Age BETWEEN 30 AND 35 

任何人都可以給我一些方向。

Answer 1

兩個方法在這個SO描述：

Oracle Pl/SQL: Loop through XMLTYPE nodes

更新：這是相當簡單的，因爲這兩種方法都是純SQL（你可以調用這個SQL在PL/SQL或任何工具與數據庫交互）：

SQL> WITH openedXml AS (
    2 SELECT extractvalue(column_value, '/theRow/First') FIRST, 
    3   extractvalue(column_value, '/theRow/Last') LAST, 
    4   to_number(extractvalue(column_value, '/theRow/Age')) Age 
    5 FROM TABLE(XMLSequence(XMLTYPE('<theRange> 
    6  <theRow><First>Bob</First><Last>Smith</Last><Age>30</Age></theRow> 
    7  <theRow><First>Sue</First><Last>Jones</Last><Age>34</Age></theRow> 
    8  <theRow><First>John</First><Last>Bates</Last><Age>40</Age></theRow> 
    9 </theRange>').extract('/theRange/theRow'))) 
10 ) 
11 SELECT * 
12 FROM openedxml 
13 WHERE age BETWEEN 30 AND 35; 

FIRST  LAST  AGE 
--------- -------- ----- 
Bob  Smith  30 
Sue  Jones  34