如何使sql查詢動態？

我正在使用這個pagination class，並正在尋找一種方法使sql查詢更具動態性，而不是硬編碼。如何使sql查詢動態？

我有一個3 <li>元素，我想要過濾按鈕，這意味着當用戶點擊這些元素之一，我想它發送的ID，所以我可以在SQL查詢中使用它。

因此對於$sql = "select * from explore where category='marketing'";（如下所示）。當用戶點擊「汽車」按鈕時，它會將上述類別更改爲汽車。

對此的任何幫助將不勝感激，謝謝。

這是我的主要頁面的樣子：

<script type="text/javascript" 
    src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> 
<script type="text/javascript" src="jquery_page.js"></script> 


<?php 
    //Include the PS_Pagination class 
    include('ps_pagination.php'); 
    //Connect to mysql db 
    $conn = mysql_connect('localhost', 'root', 'root'); 
    mysql_select_db('ajax_demo',$conn); 
    $sql = "select * from explore where category='marketing'"; 
    //Create a PS_Pagination object 
    $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=valu1&param2=value2'); 
    //The paginate() function returns a mysql 
    //result set for the current page 
    $rs = $pager->paginate(); 
    //Loop through the result set 
    while($row = mysql_fetch_assoc($rs)) { 
      echo "<table width='800px'>"; 

       echo "<tr>"; 
        echo"<td>"; 
        echo $row['id']; 
        echo"</td>"; 

        echo"<td>"; 
        echo $row['site_description']; 
        echo"</td>"; 

        echo"<td>"; 
        echo $row['site_price']; 
        echo"</td>"; 
       echo "</tr>"; 

      echo "</table>"; 
    } 

     echo "<ul id='pagination'>"; 

      echo "<li>"; 
      //Display the navigation 
      echo $pager->renderFullNav(); 
      echo "</li>"; 

     echo "</ul>"; 

    echo "<ul id='filter'>"; 

     echo "<li id='marketing'>"; 
      echo "Marketing"; 
     echo "</li>"; 

     echo "<li id='automotive'>"; 
      echo "Automotive"; 
     echo "</li>"; 

     echo "<li id='sports'>"; 
      echo "Sports"; 
     echo "</li>"; 

    echo "</ul>"; 
?>

來源

2010-03-23 ClarkSKent

http://stackoverflow.com/questions/2231538/pagination-problem-needing-assistance – CheeseConQueso 2010-03-23 19:42:20

http://stackoverflow.com/questions/1064167/php-pagination-problem-displaying-correct-content-on-additional-pages – CheeseConQueso 2010-03-23 19:42:45

http://stackoverflow.com/questions/2308169/change-queries-dynamically-php- jQuery的 – CheeseConQueso 2010-03-23 19:45:01

看起來像這條線

$pager = new PS_Pagination($conn, $sql, 8, 3, 'param1=valu1&param2=value2');

應編輯攜帶變量在運行SQL查詢之前進行測試....東西也許像：

$pager = new PS_Pagination($conn, $sql, 8, 3, 'param1=automotive&param2=sports');

那麼試試這個

if($_POST["param1"]=="automotive") 
{ 
$sql = "select * from explore where category='automotive'"; 
}

並解決它，看看你是否能得到你想要的結果。我從來沒有用過這個課，但它看起來像你將不得不玩這些params來得到你想要的結果

來源

2010-03-23 19:26:20 CheeseConQueso

如何使sql查詢動態？

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