觸發生成的ID

Question

我想在表中生成ID創建觸發器：

CREATE TABLE client (
    clientID INT PRIMARY KEY NOT NULL, 
    name VARCHAR(16) NOT NULL, 
    surname VARCHAR(16) NOT NULL, 
    personalID VARCHAR(10) NOT NULL, 
    CONSTRAINT verifyPersonalID CHECK ((personalID BETWEEN 1000000000 and 9999999999) and (MOD(personalID, 11) = 0)) 
); 

我試圖把它寫這樣，但會將返回錯誤，我不知道爲什麼。你能否給我一個建議，我做錯了什麼？

CREATE OR REPLACE TRIGGER clientID 
AFTER INSERT 
    ON client 
    FOR EACH ROW 
BEGIN 
    UPDATE client 
    SET client.clientID = klientSeq.nextval 
    WHERE :new.personalID = client.personalID; 
END; 
/

Answer 1

你想要一個前 INSERT觸發器：

CREATE OR REPLACE TRIGGER klientID 
BEFORE INSERT 
    ON klient 
    FOR EACH ROW 
BEGIN 
    SELECT klientSeq.nextval INTO :new.cisloKlienta FROM dual; 
END; 

Answer 2

也許不是創建一個觸發的，你可以使主鍵的默認值序列的下一個值。