動態獲取陣列所有元素的所有組合

-1

我正在寫代碼，讓我測試測驗排列。下面是我返回所有可能的排列數組的當前硬編碼方式。我需要適應這是動態的，因爲稍後會添加更多的數組。

我正在考慮一種方法，它可以接受一個選項數組，並返回一個排列數組，但是我的大腦在第一個循環後中斷。任何幫助將非常感激。

options = 
[ 
    [["Geek", "Chef", "Supporter", "Fashionista"]], 
    [["0-1000", "1001-10000", "No limit"]], 
    [["Many", "For One"]] 
] 


def test_gifts(options) 
    options.each_with_index do |a,index| 
    .... 
    end 
end

硬編碼的：

character_types = ["Geek","Chef", "Supporter", "Fashionista"] 
price_ranges = ["0-1,000","1,001-10000","No limit"] 
party_size  = ["Many", "For One"] 


permutations = [] 
character_types.each do |type| 
    price_ranges.each do |price| 
    party_size.each do |party| 
     permutations << [type, price, party] 
    end  
    end 
end

它返回

[["Geek", "0-1,000", "Many"], ["Geek", "0-1,000", "For One"], ["Geek", "1,001-10000", "Many"], ["Geek", "1,001-10000", "For One"], ["Geek", "No limit", "Many"], ["Geek", "No limit", "For One"], ["Chef", "0-1,000", "Many"], ["Chef", "0-1,000", "For One"], ["Chef", "1,001-10000", "Many"], ["Chef", "1,001-10000", "For One"], ["Chef", "No limit", "Many"], ["Chef", "No limit", "For One"], ["Supporter", "0-1,000", "Many"], ["Supporter", "0-1,000", "For One"], ["Supporter", "1,001-10000", "Many"], ["Supporter", "1,001-10000", "For One"], ["Supporter", "No limit", "Many"], ["Supporter", "No limit", "For One"], ["Fashionista", "0-1,000", "Many"], ["Fashionista", "0-1,000", "For One"], ["Fashionista", "1,001-10000", "Many"], ["Fashionista", "1,001-10000", "For One"], ["Fashionista", "No limit", "Many"], ["Fashionista", "No limit", "For One"]]

來源

2014-09-20 jahrichie

使用Array#product方法是：

character_types.product(price_ranges, party_size)

處理未知數量的其他陣列：

arrays_to_permute = [character_types, price_ranges, party_size] 
first_array, *rest_of_arrays = arrays_to_permute 
first_array.product(*rest_of_arrays)

來源

2014-09-20 22:01:04 Kache

我會很快接受，謝謝，知道有東西在那裏。 – jahrichie 2014-09-20 22:04:42

我認爲你的意思是'產品'，你有'排列'。（當你看到它時，我會刪除這條評論。） – 2014-09-21 00:09:06

你也可以這樣做：'arrays_to_permute.delete.product（* arrays_to_permute）'。最好不要在變量名中包含'permute'，因爲這不涉及置換。組合，是的;排列，沒有。 – 2014-09-21 00:11:20

動態獲取陣列所有元素的所有組合

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