此LPARAM現在是否正確分隔？

Question

我在收到WM_KEYDOWN事件時正在檢查LPARAM的值。但我不確定是否正確檢查了第一個16位然後是接下來的8位&等。這是MSDN如何解釋一個LPARAM是一個WM_KEYDOWN味精組織：http://msdn.microsoft.com/en-us/library/ms646280(v=vs.85).aspx

是我的位（分割？）正確?:

void outputLParam(LPARAM lParam) 
{ 
    printf("Repeat Count  : %d\n", (lParam) & ((1L<<16)-1));   // print the value of the 1st 16 bits 
    printf("Scan Code   : %d\n", (lParam >> 0x16) & ((1L<<8)-1)); // print the value of the next 8 bits 
    printf("Extended Key  : %d\n", lParam & 0x24);     // print the value of the next bit 
    printf("Reserved   : %d\n", (lParam >> 0x25) & ((1L<<4)-1)); // print the value of the next 4 bits 
    printf("Context    : %d\n", lParam & 0x29);     // print the value of the next bit 
    printf("Prev Key State  : %d\n", lParam & 0x30);     // print the value of the next bit 
    printf("Transition Key State: %d\n", lParam & 0x31);     // print the value of the next bit 
} 

Answer 1

在這裏你去。

void outputLParam(LPARAM lParam) 
{ 
    printf("Repeat Count  : %d\n", (lParam) & 0xFFFF);  // print the value of the 1st 16 bits 
    printf("Scan Code   : %d\n", (lParam >> 16) & 0xFF); // print the value of the next 8 bits 
    printf("Extended Key  : %d\n", (lParam >> 24) & 0x1); // print the value of the next bit 
    printf("Reserved   : %d\n", (lParam >> 25) & 0xF)); // print the value of the next 4 bits 
    printf("Context    : %d\n", (lParam >> 29) & 0x1); // print the value of the next bit 
    printf("Prev Key State  : %d\n", (lParam >> 30) & 0x1); // print the value of the next bit 
    printf("Transition Key State: %d\n", (lParam >> 31) & 0x1); // print the value of the next bit 
} 

Answer 2

正如我回答in your previous question，你確實應該declaring your own custom structure。它更加連貫且不易出錯。它對於這種特殊情況更爲合理，並且充分利用了語言的結構。這裏不需要任何位算術。

編輯：也就是說，安東的解決方案是正確。