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我有一個問題。在我的申請中,我打開電話簿並提取您選擇的人員的姓名和電話號碼。下面是我做的代碼:
multichose電話簿android
public void showContactsChooser(){
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, 1001);
}
@Override
public void onActivityResult(int reqCode, int resultCode, Intent data){
super.onActivityResult(reqCode, resultCode, data);
switch(reqCode){
case (1001):
if (resultCode == Activity.RESULT_OK){
ContentResolver cr = getContentResolver();
Uri contactData = data.getData();
Cursor c = cr.query(contactData, null, null, null, null);
String phone = "";
if (c.moveToFirst()){
String name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
"DISPLAY_NAME = '" + name + "'", null, null);
if (cursor.moveToFirst()) {
String contactId =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
//
// Get all phone numbers.
//
Cursor phones = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + contactId, null, null);
while (phones.moveToNext()) {
phone = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
int type = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));
switch (type) {
case ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE:
break;
}
}
phones.close();
Toast.makeText(getApplicationContext(), name + " " + phone, Toast.LENGTH_SHORT).show();
Log.d("PICK", "Contact " + name + " " + phone);
}
}
}
}
}
在這段代碼我打開電話簿,當你點擊一個聯繫人姓名,並得到一個電話號碼,然後再回到老Activiti的。但我只能選擇一個人。我需要選擇幾個。我的問題:
我可以在電話簿中選擇幾個人,然後將它們傳遞給應用程序。以及如何做到這一點?
是的,我這樣做,應用程序拉聯繫人並將其添加到列表中。但是,如果聯繫人有多個號碼,它會被複制,並且如果很多聯繫人對我不利,因爲我在應用程序服務器中有朋友,這些朋友在聯繫人下 – metalink