甲骨文像模式匹配LIKE條件

Question

我需要一個像條件使用柱像下面的 '更新'

UPDATE CUSTOMER_TRANSACTIONS ct 
SET PROCESSID = vQUARTER 
where ct.CUSTOMERID = l_arrc1(i).CUSTOMERID 
and ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID   
and ct.INVOICEID like "'"||l_arrc1(i).INVOICEID||%||"'"; 

代替

UPDATE CUSTOMER_TRANSACTIONS ct 
SET PROCESSID = '2015Q4' 
where ct.CUSTOMERID = l_arrc1(i).CUSTOMERID 
and ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID   
and ct.INVOICEID like '0158741%'; 

的INVOICEID和l_arrc1(i).INVOICEID是VARCHAR

怎麼做？

Answer 1

假設INVOICEID是number列：

UPDATE customer_transactions ct 
    SET processid = vQUARTER 
WHERE ct.customerid = l_arrc1(i).customerid 
    AND ct.appointofcaid = l_arrc1(i).appointofcaid 
    AND to_char(ct.invoiceid) LIKE to_char(l_arrc1(i).INVOICEID) || '%'; 

如果invoiceid不是number數據類型，那麼你可以刪除to_char

Answer 2

你缺少的字符串分隔符合適，單引號：

UPDATE CUSTOMER_TRANSACTIONS ct 
    SET PROCESSID = vQUARTER 
    WHERE ct.CUSTOMERID = l_arrc1(i).CUSTOMERID and 
      ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID and  
      ct.INVOICEID LIKE l_arrc1(i).INVOICEID || '%' ; 

字符串在SQL適當的分隔符是單引號，而不是雙引號。