避免XMPP消息「無法SUBCRIBE自己」

我有以下代碼啓動兩個用戶之間的聊天對話：避免XMPP消息「無法SUBCRIBE自己」

   // Create Connection. 
       Connection.DEBUG_ENABLED = true; 
       config  = new ConnectionConfiguration(CHAT_SERVER); 
       connection = new XMPPConnection(config); 
       connection.connect(); 
       connection.login(chatLogin, password); 

       // Create Chat Manager. 
       chatManager = connection.getChatManager(); 

       // Create Chat. 
       chat = chatManager.createChat(friendLogin, messageListener); 

       // Set listener for outcoming messages. 
       chatManager.addChatListener(chatManagerListener); 

       String str_your_chat_id  = Integer.toString(your_chat_id); 
       String str_receiver_chat_id = Integer.toString(receiver_chat_id); 

       // Set Subscription to receive user status 
       Presence subscribe = new Presence(Presence.Type.subscribe); 
       subscribe.setTo(str_your_chat_id +"[email protected]"); 
       connection.sendPacket(subscribe); 

       Presence subscribed = new Presence(Presence.Type.subscribed); 
       subscribed.setTo(str_receiver_chat_id +"[email protected]"); 
       connection.sendPacket(subscribed); 


       subscribe = new Presence(Presence.Type.subscribe); 
       subscribe.setTo(str_receiver_chat_id +"[email protected]"); 
       connection.sendPacket(subscribe); 


       subscribed = new Presence(Presence.Type.subscribed); 
       subscribed.setTo(str_your_chat_id +"[email protected]"); 
       connection.sendPacket(subscribed);

但它運行的消息從asmack服務器來時迴應說，「你不能訂閱你自己「。

任何人有關於我在做什麼錯的想法？

來源

2014-02-21 MarcForn

蹊蹺的驗證碼

  // Set Subscription to receive user status 
      Presence subscribe = new Presence(Presence.Type.subscribe); 
      subscribe.setTo(str_your_chat_id +"[email protected]"); 
      connection.sendPacket(subscribe);

你爲自己做的一個訂閱，但你不知道

將是巨大的聽到你想實現

什麼

來源

2014-03-02 13:35:32

避免XMPP消息「無法SUBCRIBE自己」

回答

相關問題