1
我可能是盲目的,但我無法解釋爲什麼查詢甲骨文:報價表名
SELECT "VALUE" AS value
FROM "TEST_INT"
WHERE "ID" = 20;
作品,但
SELECT "VALUE" AS value
FROM "TEST_INT" AS "TTT"
WHERE "ID" = 20;
沒有。
我的SQL開發人員回覆
ORA-00933: SQL command not properly ended
00933. 00000 - "SQL command not properly ended"
*Cause:
*Action:
Error at Line: 2 Column: 19
難道我引用表錯誤的名字嗎?
啊,非常感謝! – gefei
+1是的,就是這樣! – Parado