我忙於創建訂單系統。PHP/HTML - 表單輸入問題 - 將多個帖子轉換爲一個
我有問題試圖創建只需要一個訂單按鈕的窗體。
當前表格是針對每個產品的結果。用戶可以輸入所需數量的產品,然後根據所選數量訂購產品。然後將選定的商品標識和數量添加到會話中。
問題在於,如果有5個項目,則有5個順序按鈕。
我想簡化這個,在5種產品中,只有一個訂單按鈕控制整個產品的選擇。
這裏是代碼與此:
//Now we search for our search term, in the field the user specified
$dataQuery = "SELECT * FROM `products` WHERE upper(`desc`) LIKE '%"
. implode("%' AND upper(`desc`) LIKE '%", $keywords_array)
. "%' ORDER BY `desc`";
$data = mysql_query($dataQuery) or die(mysql_error());
$tempVar = 0;
//And we display the results
while ($result = mysql_fetch_array($data)) {
$prId = $result['id'];
$prRefCode = $result['refCode'];
$prDesc = $result['desc'];
$prPack = $result['pack'];
$prMeasure = $result['measure'];
$prQuantity = $result['quantity'];
$prDeptCode = $result['deptCode'];
$prTaxable = $result['taxable'];
$prPrice1 = $result['price1'];
$prPrice2 = $result['price2'];
$prCrdCode = $result['crdCode'];
$prCost1 = $result['cost1'];
$prCost2 = $result['cost2'];
if ($tempVar == 0) {
$pageContent .= '
<p><u>All prices are inclusive of VAT</u></p>
<table class="searchResults" border="1" align="center" width="90%">
<thead>
<tr>
<th>Stock Code</th>
<th>Description</th>
<th>Packsize</th>
<th>Price</th>
<th>In-Stock?</th>
<th>Quantity</th>
<th>Submit</th>
</tr>
</thead>
<tbody>
';
}
$pageContent .= '
<tr>
<td>' . $prId . '</td>
<td>' . $prDesc . '</td>
<td>' . $prPack . 'x' . $prSize . ' ' . $prMeasure . '</td>
<td>R' . $prPrice1 . '</td>
';
if (empty($prQuantity)) {
$pageContent .= '
<td>No</td>
';
} else {
$pageContent .= '
<td>Yes</td>
';
}
$pageContent .= '
<form id="validated" action="" method="post">
<td>
<div>
<input type="text"
onkeydown="return (event.ctrlKey || event.altKey
|| (47<event.keyCode && event.keyCode<58 && event.shiftKey==false)
|| (95<event.keyCode && event.keyCode<106)
|| (event.keyCode==8) || (event.keyCode==9)
|| (event.keyCode>34 && event.keyCode<40)
|| (event.keyCode==46))"
name="quantity" size ="2"
value ="1"
style="background: #F4F4F4;
font-family: Monaco, monospace;" />
</div>
</td>
<td>
<div>
<input type="hidden" name="id" value="' . $prId . '" />
<input type="submit" name="action" value="Order" />
</div>
</td>
</form>
</tr>
';
$tempVar ++;
}
//This counts the number of results - and if there wasn't any it gives them a little message explaining that
$anymatches = mysql_num_rows($data);
if ($anymatches == 0) {
$pageContent .= '
<p>Sorry, but we can not find an entry to match your query</p>
<!-- end .aliLeft --></div>
';
}
if ($anymatches > 0 and count($tempVar) == count($anymatches)) {
$pageContent .= '
</tbody>
</table>
<!-- end .aliLeft --></div>
';
}
這裏是代碼控制用戶點擊的訂購按鈕實例:
if (!isset($_SESSION['order']))
{
$_SESSION['order'] = array();
}
if (!isset($_SESSION['quantity']))
{
$_SESSION['quantity'] = array();
}
if (isset($_POST['action']) and $_POST['action'] == 'Order' and $_POST['quantity'] > 0)
{
// Add item to the end of the $_SESSION['order'] array
$_SESSION['order'][$_POST['id']] = $_POST['id'];
$_SESSION['quantity'][$_POST['id']] = $_POST['quantity'];
header('Location: .');
exit();
}
這裏是代碼,用於配置總訂單的數量值:
$total = 0;
if (count($order) > 0)
{
foreach ($order as $product)
{
mysql_data_seek($totalsSql, 0); //<- this line, to reset the pointer for every EACH.
while($row = mysql_fetch_assoc($totalsSql))
{
$prodId = $row['id'];
$prodPrice1 = $row['price1'];
$prodQuantity = $quantity[$prodId];
if ($product == $prodId)
{
$total += ($prodPrice1*$prodQuantity);
break;
}
}
}
}
正如您所看到的,當用戶搜索產品,查詢mysql表,如果找到結果,則返回它們。
在此過程中,將爲每個結果創建表單。
我想要做的是擴展這個表單來覆蓋整個結果集,然後只有一個輸入用於「Order」,所以基本上,用戶可以在各種產品上輸入數量,然後讓這些產品和數量添加到他們的訂單。
有沒有人有任何建議,我會如何去做這項工作?
我將不勝感激任何輸入,所以永遠謝謝!
首先,不要使用相同的'ID'標記值的兩倍。它們應該是唯一的。 – yoda