Python：如何知道兩個字典是否有相同的密鑰

Question

dic1 = {'a':'a','b':'c','c':'d'} 
dic2 = {'b':'a','a':'c','c':'d'} 

dic1.keys() =>['a', 'b', 'c'] 
dic2.keys() =>['b', 'a', 'c'] 

dic1和dic2具有相同的密鑰，但順序不同。

如何判斷它們是否有相同的鍵（不考慮順序）？

Answer 1

蟒蛇2.7

dict views： 支持直接操作集等

>>> dic1 = {'a':'a','b':'c','c':'d'} 
>>> dic2 = {'b':'a','a':'c','c':'d'} 
>>> dic1.viewkeys() == dic2.viewkeys() 
True 
>>> dic1.viewkeys() - dic2.viewkeys() 
set([]) 
>>> dic1.viewkeys() | dic2.viewkeys() 
set(['a', 'c', 'b']) 

同樣在3.X：（THX @lennart）

>>> dic1 = {'a':'a','b':'c','c':'d'} 
>>> dic2 = {'b':'a','a':'c','c':'d'} 
>>> dic1.keys() == dic2.keys() 
True 
>>> dic1.keys() - dic2 
set() 
>>> dic1.keys() | dic2 
{'a', 'c', 'b'} 

蟒蛇2.4 +

set operation：直接迭代過字典的鍵成一組

>>> dic1 = {'a':'a','b':'c','c':'d'} 
>>> dic2 = {'b':'a','a':'c','c':'d'} 
>>> set(dic1) == set(dic2) 
True 

Answer 2

set(dic1.keys()) == set(dic2.keys()) 

Answer 3

我不知道你怎麼落幕讓keys()回報，你的無序列表，但sorted(dict1.keys()) == sorted(dict2.keys())應該這樣做。

Answer 4

我們可以使用所有

all(k in dic2 for k in dic1) and all(k in dic1 for k in dic2)