Python中的二進制和Denary轉換器

Question

我對python很陌生，我想創建一個二進制到十進制轉換器和一個小數到二進制轉換器。

然而二進制數的用戶要轉換隻能是八位長，必須是一個有效的二進制數，而用戶想要轉換隻能是積極的deciamal數量和最多255

我想出了這個代碼，我堅持'然而'部分。

import time 

def program(): 
    a = input ("Would you like to convert Denary To Binary (D) or Binary To Denary (B)? ") 

if a == ("D") : 

    def denary(): 
     print("The denary number you want to convert, can only be a positive number up to 255") 
     time.sleep(2) 
     e= int(input("What number would you like to convert into Binary? ")) 
     if e < 255 or e==255 or e >= 0: 
      print(bin(e)[2:].zfill(8)) 
      again=int(input("Would you like to go again YES[1] NO[2]")) 
      if again==(1): 
       program() 
      else: 
       print ("Thank you for using the program")  

     else: 
      denary() 


    denary() 




elif a == ("B"): 

    def binary(): 
     print("The binary number you want to convert, can only be eight digits long and can only be a valid binary, number consiting of 0's and 1's") 
     time.sleep(2)  
     c = int(input("What Binary number would you like to convert into Denary? ")) 
     if len(c) >8 and c== '0' or '1': 
      convert= lambda b: str(int(b, 2)) 
      print(c + " is " + convert(c) + " in Denary") 
      again=int(input("Would you like to convert a number again YES[1] NO[2]")) 
      if again==(1): 
       program() 

      else: 
       print ("Thank you for using the program") 

     else: 
      binary() 

    binary()  


else: 
    program() 

program() 

Answer 1

 if e < 255 or e==255 or e >= 0: 

你不想or這裏。如果至少有一個條件爲真，則將採用此分支。 1000滿足e >= 0，所以1000通過支票。 -1000滿足e < 255，所以-1000通過支票。事實上，每一個數字都會經過這裏。你想

if e >= 0 and e <= 255: 

，或者使用Python的比較鏈接，

if 0 <= e <= 255: 

---

 if len(c) >8 and c== '0' or '1': 

這是沒有意義的。

• 首先，c已經是int;你試圖把它作爲一個字符串來操作。

• 其次，長度測試不應該檢查長度更大比8.應當== 8如果你需要若有長度精確匹配或<= 8多達8個作品。

• 第三，and之後的部分是沒有意義的。 x == y or z不測試x是否等於y或z中的一個。它被解釋爲(x == y) or z，這通常是無稽之談。

• 最後，即使c== '0' or '1'測試c是否的'0'或'1'之一，仍然不會是一件有意義的事情要做。如果你想測試在c的所有字符是否是'0'或'1'，可以使用all與發電機表達式：

  所有（在（「0」，「1」碳）在C炭）

解決所有這些問題，我們有以下幾點：

c = input("What Binary number would you like to convert into Denary? ") 
if len(c) == 8 and all(char in ('0', '1') for char in c): 

Answer 2

這裏是基本的轉換功能，應該讓你去：

def dec2bin(N): 
    if not N: 
     return '' 
    else: 
     return dec2bin(N//2) + str(N%2) 

def bin2dec(b): 
    answer = 0 
    for char in b: 
     answer *= 2 
     answer += int(char) 
    return answer 

def program(): 
    answer = input("Do you want to convert decimal to binary (D) or ...: ") 
    if answer == "D": 
     N = int(input("Enter your number: ")) 
     print("The binary of %s is %s" %(N, dec2bin(N))) 

    # remainder of the UI logic goes here 

Answer 3

槓桿的內建！

月至斌：

def to_bin(n): #assuming n is a str 
    """If the str n represents a number in the range [0, 256), return a 
    binary string representation of that number, otherwise raise a ValueError 

    """ 
    if 0 <= int(n) < 256: # if n is in the valid range 
     return bin(int(n))[2:] #builtin :p 
    else: 
     raise ValueError('number must be in range [0, 256)') 

倉至十二月

def to_dec(n): 
    """If the str n is at most 8 characters long and consists only of '0' and 
    '1' characters, return the decimal string representation of it, otherwise 
    raise a ValueError 

    """ 
    if len(n) <= 8 all(c in ('0', '1') for c in n): 
     return str(int(n, 2)) 
    else: 
     raise ValueError('binary number must be <= 8 digits and consist of 0 and 1')