寫PL/SQL博客陳述

Question

假設我們有員工表，我的目標是編寫declare -blog statment，它將該員工的工資提高10％，在工作部門有更高的工資水平，並且由20 ％如果它沒有更多的薪金， 我認爲代碼應該是

begin 
update employees e set e.salary=e.salary+e.salary*0.1; 
where e.salary>(select avg(e.salary) from employees e group by e.department_id); 
update employees e set e.salary=e.salary+e.salary*0.1; 
where e.salary<(select avg(e.salary) from employees e group by e.department_id); 



end; 

但它返回下列錯誤列表，

Error starting at line 4 in command: 
begin 
update employees e set e.salary=e.salary+e.salary*0.1; 
where e.salary>(select avg(e.salary) from employees e group by e.department_id); 
update employees e set e.salary=e.salary+e.salary*0.1; 
where e.salary<(select avg(e.salary) from employees e group by e.department_id); 



end; 
Error report: 
ORA-06550: line 3, column 1: 
PLS-00103: Encountered the symbol "WHERE" when expecting one of the following: 

    (begin case declare end exception exit for goto if loop mod 
    null pragma raise return select update while with 
    <an identifier> <a double-quoted delimited-identifier> 
    <a bind variable> << continue close current delete fetch lock 
    insert open rollback savepoint set sql execute commit forall 
    merge pipe purge 
06550. 00000 - "line %s, column %s:\n%s" 
*Cause: Usually a PL/SQL compilation error. 
*Action: 

請幫幫我，爲什麼？，是有必要的循環statment或？

Answer 1

取出;上

update employees e set e.salary=e.salary+e.salary*0.1; 

的;終止的發言，但你繼續它WHERE

Answer 2

您where之前有一個分號（;）;分號關閉PL/SQL語句。

我也建議你格式化報表的方式，使得它更易於閱讀和難以犯了一個錯誤：

update employees e set 
    e.salary=e.salary+e.salary*0.1 -- no semicolon here 
where 
    e.salary > (
     select avg(e.salary) 
     from employees e 
     group by e.department_id 
    );