如何在不重疊的情況下產生多個節點？

Question

我喜歡，所以我的屏幕上的每一個節點0.2-5.0秒產卵：

override func didMoveToView(view: SKView) { 
    backgroundColor = UIColor.whiteColor() 

    runAction(SKAction.repeatActionForever(
     SKAction.sequence([ 
      SKAction.runBlock(blackDots), 
      SKAction.waitForDuration(1.0)]))) 
} 

func random() -> CGFloat { 
    return CGFloat(Float(arc4random())/0xFFFFFFFF) 
} 

func random(min min: CGFloat, max: CGFloat) -> CGFloat { 
    return random() * (max - min) + min 
} 

func blackDots() { 
    let dot = SKSpriteNode(imageNamed: "first@2x") 
    dot.size = CGSizeMake(75, 75) 
    dot.name = "dotted" 
    dot.position = CGPointMake(500 * random(min: 0, max: 1), 500 * random(min: 0, max: 1)) 
    addChild(dot) 
} 

然而，當他們被催生，有的交叉，躺在彼此頂部？有沒有辦法來防止這種情況？提前致謝。

Answer 1

以下是如何檢查節點是否存在於特定位置的方法。

您可能希望將支票放入循環中，以便如果取得該位置，它將使用新生成的點重試。否則，你會得到一些不會顯示的點。取決於你在做什麼。

override func didMoveToView(view: SKView) { 
    backgroundColor = UIColor.whiteColor() 

    runAction(SKAction.repeatActionForever(
     SKAction.sequence([ 
      SKAction.runBlock(blackDots), 
      SKAction.waitForDuration(1.0)]))) 
} 

func random() -> CGFloat { 
    return CGFloat(Float(arc4random())/0xFFFFFFFF) 
} 

func random(min min: CGFloat, max: CGFloat) -> CGFloat { 
    return random() * (max - min) + min 
} 

func blackDots() { 
    let dot = SKSpriteNode(imageNamed: "first@2x") 
    dot.size = CGSizeMake(75, 75) 
    dot.name = "dotted" 

    let position = CGPointMake(500 * random(min: 0, max: 1), 500 * random(min: 0, max: 1)) 

    if positionIsEmpty(position) { 
     dot.position = position 
     addChild(dot) 
    } 
} 

func positionIsEmpty(point: CGPoint) -> Bool { 
    self.enumerateChildNodesWithName("dotted", usingBlock: { 
     node, stop in 

     let dot = node as SKSpriteNode 
     if (CGRectContainsPoint(dot.frame, point)) { 
      return false 
     } 
    }) 
    return true 
} 

Answer 2

這裏是這迅速3.1請注意，這也需要好幾個小時也成功地重新創建一個for循環或TimerInterval將無法正常運行這個它是一系列動作

這樣

let wait = SKAction.wait(forDuration: 1) 
    let spawn = SKAction.run { 
     //be sure to call your spawn function here 
     example() 
    } 
    let sequence = SKAction.sequence([wait, spawn]) 
    self.run(SKAction.repeatForever(sequence)) 

，如果這是正確的做它應該像我有

func example() { 
    //the person node is equal to an SKSpriteNode subclass 
    person = people() 
    func random() -> CGFloat { 
    //this is the random spawn generator increasing or decreasing these two numbers will change how far or how close they spawn together 
     return CGFloat(Float(arc4random_uniform(UInt32(500 - 343)))) 
    } 

    func random(min: CGFloat, max: CGFloat) -> CGFloat { 
     return random() * (max - min) + min 
    } 

    func spawnPeople() { 
     //note that this is set to spawn them on the x-axis but can easily be changed for the y-axis 
     let position = CGPoint(x: 2 * random(min: 0, max: 1),y: -290) 

     if positionIsEmpty(point: position) { 
     //set the position of your node and add it to the scene here any actions you want to add to the node will go here 
      person.position = position 
      self.addChild(person) 
      //example 
      person.run(parallax1) 
     } 
    } 

    func positionIsEmpty(point: CGPoint) -> Bool { 
     if (person.frame.contains(point)) { 
      print("failed") 
      return false 
     } 
     print("success") 
     return true 
    } 
    //make sure to call the spawn(name)() function down here or the code will not run 
    spawnPeople() 
} 

我也有我的didMoveToView函數中的所有代碼