內聯循環Python。檢查列表中的每個成員到另一個列表內嵌

Question

我有一個問題，我一直想要問一下現在。我有一些代碼，我試圖檢查每個項目的引用列表朝向另一個列表，所有這些INLINE。例如：

if int(word[:-1])>=1 and int(word[:-1])<=31 and for word in LIST1, word in LIST2: 
       day = word[:-1] 

更具體地，這是數據刮程序來篩選出的數據的各種領域，例如日期和月份的一部分。

months = ["January","February",etc......] 
days = ["monday,","tuesday,","wednesday,","thursday,","friday,","saturday,","sunday,"] 
if word.lower() in days and For i in line.split(), months.contains(i) 

因此，例如，在list1中，我每週都有一天。如果LIST2包含一週中的任何一天（不是全部），則這將評估爲真。有誰知道一個光滑的方式來做到這一點？謝謝。

Answer 1

if set(list2) & set(list1): 
    print "there is something in list2 that matches something in list1" 

print "The days in list2 are", set(list2) & set(list1) 

等