如何在PHP中傳遞sql中的變量？

Question

我用這個SQL查詢之間的時間間隔來獲取數據

$start_time = $_POST['i_date'].' 07:00:00'; 
$end_time = $_POST['i_date'].' 14:00:00'; 
/*echo $start_time; 
die();*/ 
$sql = 'select * from datetime where code = 1001 and time between '.$start_time.' and '.$end_time; 

但我得到以下錯誤信息： 查詢無效：您的SQL語法錯誤;請檢查與您的MySQL服務器版本對應的手冊，以便在第1行'07:00:00和2015-09-09 14:00:00'使用正確的語法。

Answer 1

您的查詢有錯誤請嘗試此操作

$sql = "select * from datetime where code = 1001 and time between '".$start_time."' and '".$end_time."'"; 

Answer 2

你必須把字符串中的分號你傳遞：

$sql = 'select * from datetime where code = 1001 and time between '.$start_time.' and '.$end_time. ';'; 

Answer 3

捆成單引號：

$sql = "select * from datetime where 
code = 1001 and time between 
'$start_time' and '$end_time'";