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我的Java程序對於我的課程有問題。我必須創建一個程序,提示用戶輸出文件的路徑和名稱,該文件將具有我的程序將採用的公式的係數行,並使用二次公式計算解。到目前爲止,我認爲除了我的輸出文件外,一切正常。假設我有一個包含3行係數的輸入文件,我的程序將在控制檯流中顯示解決方案,但僅在我的輸出文件中顯示1行解決方案。這是我第一次和我一起光顧的java課程!我在這裏先向您的幫助表示感謝!僅輸出一行代碼的Java程序
while (input.hasNext()) {
a = input.nextInt();
b = input.nextInt();
c = input.nextInt();
discriminant = Math.pow(b, 2) - 4 * a * c;
///There will be no solutions if discriminant<0
if (discriminant < 0){
System.out.println("There are no solutions.");
output.println("There are no solutions.");
}
///As with the above, if coefficent a = 0 no solutions
else if (a == 0){
System.out.println("There are no solutions.");
output.println("There are no solutions.");
}
else if (discriminant == 0){
solutionOne = (-b + Math.sqrt(discriminant))/(2 * a);
if (b < 0) {
System.out.printf("%3.0fx^2 %3.0fx + %3.0f, has one solution:%5.3f%n",a,b,c,solutionOne);
output.printf("%3.0fx^2 %3.0fx + %3.0f has one solution:%5.3f%n",a,b,c,solutionOne);
}
else{
System.out.printf("%3.0fx^2 %3.0fx + %3.0f has one solution:%5.3f%n",a,b,c,solutionOne);
output.printf("%3.0fx^2 %3.0fx + %3.0f has one solution:%5.3f%n",a,b,c,solutionOne);
}
}
else if(discriminant>0){
solutionOne=(-b + Math.sqrt(discriminant))/(2*a);
twoSolutions=(-b - Math.sqrt(discriminant))/(2*a);
if(b<0){
System.out.printf("%3.0fx^2 %3.0fx + %3.0f has two solutions: %5.3f %5.3f%n",a,b,c,solutionOne,twoSolutions);
output.printf("%3.0fx^2 %3.0fx + %3.0f has two solutions:5.3f %5.3f%n",a,b,c,solutionOne,twoSolutions);
}
else{
System.out.printf("%3.0fx^2 %3.0fx + %3.0f has two solutions:%5.3f %5.3f%n",a,b,c,solutionOne,twoSolutions);
output.printf("%3.0fx^2 %3.0fx + %3.0f has two solutions: %5.3f%5.3f%n",a,b,c,solutionOne,twoSolutions);
}
}
output.close();
顯然是正確的答案。 –