XNA保持和點擊同一對象上

如果在一場比賽中同一個對象有點擊它並按住鼠標點擊了它，使用默認輸入（當前和最後MouseState）兩個不同的動作，你就會激活即使在您持有的情況下也可以點擊操作例如，您使用該按鈕拖動n'將一個對象拖放到屏幕上，但是當您單擊它時，它應該消失。當你點擊物體移動它時，它會消失，這是一個不想要的結果。XNA保持和點擊同一對象上

MouseState current, last; 

public void Update(GameTime gameTime) { 
    current = Mouse.GetState(); 

    bool clicked = current.LeftButton == ButtonState.Pressed && last.LeftButton == ButtonState.Released; 
    bool holding = current.LeftButton == ButtonState.Pressed; 

    if(clicked) vanishObject(); 
    if(holding) moveObject(current.X, current.Y); 

    last = current; 
}

我想用一個標誌，「舉行了超過N秒」來解決它，穿上ReleasedClick的消失，檢查標誌，但改變事件時間似乎並沒有成爲一個優雅的解決方案。有任何想法嗎？

來源

2012-02-11 Mephy

感謝大家回答我，但沒有人改變了事實，以實現點擊發布事件，而不是Press。 – Mephy 2012-02-15 16:13:25

您應該改變消除對象的邏輯。你真正想要的是

if (clicked && !holding) vanishObject();

這應該是獲得你想要的最簡單的方法。

來源

2012-02-11 18:36:51

你在想點擊走錯了路。實現這種行爲的最簡單方法是，只有當mouseState被按下最後一幀並且釋放該幀，並且如果沒有達到特定時間，才觸發點擊操作。代碼：

private const float HOLD_TIMESPAN = .5f; //must hold down mouse for 1/2 sec to activate hold 
MouseState current, last; 
private float holdTimer; 

public virtual void Update(GameTime gameTime) 
{ 
    bool isHeld, isClicked; //start off with some flags, both false 
    last = current; //store previous frame's mouse state 
    current = Mouse.GetState(); //store this frame's mouse state 
    if (current.LeftButton == ButtonState.Pressed) 
    { 
     holdTimer += (float)gameTime.ElapsedTime.TotalSeconds(); 
    } 
    if (holdTimer > HOLD_TIMESPAN) 
     isHeld = true; 
    if (current.LeftButton == ButtonState.Released) 
    { 
     if (isHeld) //if we're releasing a held button 
     { 
      holdTimer = 0f; //reset the hold timer 
      isHeld = false; 
      OnHoldRelease(); //do anything you need to do when a held button is released 
     } 
     else if (last.LeftButton == ButtonState.Pressed) //if NOT held (i.e. we have not elapsed enough time for it to be a held button) and just released this frame 
     { 
      //this is a click 
      isClicked = true; 
     } 
    } 
    if (isClicked) VanishObject(); 
    else if (isHeld) MoveObject(current.X, current.Y); 
}

當然這個代碼有一些優化的空間，但我認爲這是足夠明智的。

來源

2012-02-11 18:40:38

我認爲它更好地檢查鼠標位置，如果釋放與點擊位置相同，則會被點擊，否則會被拖動 – 2015-08-17 14:22:16

const float DragTimeLapsus = 0.2f; 

    if (current.LeftButton == ButtonState.Released) time = 0; 
    else time+= ElapsedSeconds; 

    bool clicked = current.LeftButton == ButtonState.Released 
       && last.LeftButton == ButtonState.Pressed 
       && time<DragTimeLapsus; 
    bool holding = current.LeftButton == ButtonState.Pressed 
       && last.LeftButton == ButtonState.Pressed 
       && time>DragTimeLapsus ;

來源

2012-02-11 19:58:21 Blau

XNA保持和點擊同一對象上

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