首先,使用枕頭可能是最好的解決方案,特別是因爲你可以download windows binaries from pypi。
快速谷歌搜索得到this pure-python function得到GIF,PNG和JPEG圖像的大小:
import struct
from cStringIO import StringIO
def get_image_info(data):
"""
Return (content_type, width, height) for a given img file content
no requirements
"""
data = str(data)
size = len(data)
height = -1
width = -1
content_type = ''
# handle GIFs
if (size >= 10) and data[:6] in ('GIF87a', 'GIF89a'):
# Check to see if content_type is correct
content_type = 'image/gif'
w, h = struct.unpack("<HH", data[6:10])
width = int(w)
height = int(h)
# See PNG 2. Edition spec (http://www.w3.org/TR/PNG/)
# Bytes 0-7 are below, 4-byte chunk length, then 'IHDR'
# and finally the 4-byte width, height
elif ((size >= 24) and data.startswith('\211PNG\r\n\032\n')
and (data[12:16] == 'IHDR')):
content_type = 'image/png'
w, h = struct.unpack(">LL", data[16:24])
width = int(w)
height = int(h)
# Maybe this is for an older PNG version.
elif (size >= 16) and data.startswith('\211PNG\r\n\032\n'):
# Check to see if we have the right content type
content_type = 'image/png'
w, h = struct.unpack(">LL", data[8:16])
width = int(w)
height = int(h)
# handle JPEGs
elif (size >= 2) and data.startswith('\377\330'):
content_type = 'image/jpeg'
jpeg = StringIO(data)
jpeg.read(2)
b = jpeg.read(1)
try:
while (b and ord(b) != 0xDA):
while (ord(b) != 0xFF): b = jpeg.read
while (ord(b) == 0xFF): b = jpeg.read(1)
if (ord(b) >= 0xC0 and ord(b) <= 0xC3):
jpeg.read(3)
h, w = struct.unpack(">HH", jpeg.read(4))
break
else:
jpeg.read(int(struct.unpack(">H", jpeg.read(2))[0])-2)
b = jpeg.read(1)
width = int(w)
height = int(h)
except struct.error:
pass
except ValueError:
pass
return content_type, width, height
注意,對博客的代碼被寫了靈光VAÏSSE。他的博客上沒有指定許可證,因此取決於您想要包含代碼的位置可能想要重新實現該功能或要求他在安全網站上。
如果擴展模塊的分佈是問題,則可以創建包含預構建二進制文件的輪子。 – delnan
pypi上有可用於枕頭的窗口二進制文件:https://pypi.python.org/pypi/Pillow/2.2.1 – ThiefMaster