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因此,我正在創建一個表,我要顯示4個數據字段,3個來自一個表,1個來自另一個表。我曾嘗試使用聯合和其他一些方法,但它似乎不起作用。整個代碼如下。下面給出了我試圖從中獲取數據的2個表的截圖。一次從2個不同的表中獲取數據而不加入php
表:http://gyazo.com/a0839ffc4f5c9cb51458b2b01006c745
我一直想(SQL不是PHP代碼):
SELECT FirstName, LastName, Rating FROM guest WHERE Rating = 5 UNION ALL SELECT Suburb FROM suburb WHERE Suburb = 'Booragoon';
這是PHP代碼:
<?php
echo "<table style = 'border; solid 1px black;'>"
echo "<tr><th>First Name</th><th>Last Name</th><th>Suburb</th><th>Rating</th></tr>";
class TableRows extends RecursiveInteratorInterator {
function __construct($it) {
parent::__construct($it, self::LEAVES_ONLY);
}
function current() {
return "<td style='width:160px;border:1px solid black;'>" . parent::curren(). "</td>";
}
function beginChildren(){
echo "<tr>";
}
function endChildren() {
echo "</tr>" . "\n";
}
}
$Suburb = $_POST['InputSuburb'];
$Rating = $_POST['InputRating'];
$username = 'root';
$password = '';
$conn = new PDO('mysql:host=localhost;dbname=pizza_shop' $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare//where the command is going
$stmt->bindParam('Suburb',$Suburb, PDO::PARAM_STR);
$stmt->execute();
?>
您在這兩個查詢中沒有相同的列數。爲什麼你想要它沒有加入? –
@Ameya Deshpande會不會破壞結構?如果不是,我會很樂意使用連接 – csharpnewbie