複雜的PHP對象JSon字符串

Question

我有一個複雜的對象在PHP，需要解析它來建立一個JSON字符串。我發現了很多我在這裏和其他網站找到的exmaples，但沒有人工作。進一步的問題是，我的託管在PHP 5.2上工作，我無法升級。

這裏是我的var_dump($myObj)一個例子：

object(Park)[4] 
private 'idObj' => string '60304' (length=5) 
private 'name' => string 'AlphaSurf' (length=9) 
private 'address' => 
object(Address)[6] 
    private 'idObj' => string '40304' (length=5) 
    private 'street' => string 'Champ de la Vigne' (length=17) 
    private 'number' => string '7' (length=1) 
    private 'zip' => string '1470' (length=4) 
    private 'city' => string 'Estavayer-le-Lac' (length=16) 
    private 'country' => 
    object(Country)[8] 
     private 'idObj' => string '30039' (length=5) 
     private 'name' => string 'Switzerland' (length=11) 
     private 'flag' => string 'switzerland.gif' (length=15) 
    private 'usState' => null 
private 'contactInfo' => 
object(ContactInfo)[7] 
    private 'idObj' => string '70304' (length=5) 
    private 'phone' => string '' (length=0) 
    private 'email' => string '' (length=0) 
    private 'emailcode' => null 
    private 'confirmed' => string '1' (length=1) 
    private 'website' => string 'www.alphasurf.ch' (length=16) 
    private 'mobile' => string '' (length=0) 
    private 'fax' => string '' (length=0) 
    private 'newsletter' => string '0' (length=1) 
private 'owner' => 
object(User)[9] 
    private 'idObj' => string '50001' (length=5) 
    private 'username' => string 'emaborsa' (length=8) 
    private 'password' => string '5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8' (length=40) 
    private 'type' => string 'ADMIN' (length=5) 
    private 'state' => string 'ACTIVE' (length=6) 
    private 'ip' => string '' (length=0) 
    private 'time' => string '0' (length=1) 
    private 'address' => null 
    private 'contactInfo' => 
    object(ContactInfo)[11] 
     private 'idObj' => string '1' (length=1) 
     private 'phone' => null 
     private 'email' => string 'info@emaborsa.com' (length=17) 
     private 'emailcode' => null 
     private 'confirmed' => string '1' (length=1) 
     private 'website' => null 
     private 'mobile' => null 
     private 'fax' => null 
     private 'newsletter' => string '1' (length=1) 
private 'logo' => string 'Champ de la Vigne 71470' (length=23) 
private 'xcoord' => string '46856912' (length=8) 
private 'ycoord' => string '6846918' (length=7) 
private 'state' => string 'HIDDEN' (length=6) 
private 'detail' => 
object(ParkDetail)[10] 
    private 'idObj' => string '1' (length=1) 
    private 'descriptionIT' => string '' (length=0) 
    private 'descriptionEN' => string '' (length=0) 
    private 'descriptionDE' => string 'xcxcx' (length=5) 
    private 'type' => string '' (length=0) 
    private 'kickers' => string '0' (length=1) 
    private 'boxes' => string '0' (length=1) 
    private 'rails' => string '0' (length=1) 
    private 'specials' => string '0' (length=1) 
    private 'specialsDescriptionIT' => null 
    private 'specialsDescriptionEN' => null 
    private 'specialsDescriptionDE' => null 
    private 'dimension' => string '0' (length=1) 
private 'lastPayment' => null 

所有屬性是私有的，但也有公共getter和setter。

Answer 1

試試這個

public function encodeJSON() 
{  
    foreach ($this as $key => $value) 
    { 
     if($value instanceOf(stdClass)){ 
      $json->$key = $value->encodeJSON(); 
     }else 
      $json->$key = $value; 
    } 
    return json_encode($json); 
} 

我試圖私有成員轉移到可以通過正常json_encode()和第6行我打電話是遞歸的foreach參數，如果它不是一個靈長類動物被寫入新對象鍵入

Answer 2

當您運行PHP < 5.4時，我建議在您的對象中創建一個toArray方法，返回一個包含所有屬性的數組（無需打擾它們是公共的，私有的還是受保護的）。

例如：

public class Park { 

    private $idObj; 
    private $address; 

    public function toArray() { 

     $toArray = array(
      'idObj' => $this->idObj, 
      'address' => $this->address->toArray() // Assuming address is an Address object 
     ); 
    } 
} 

爲此在所有的類和子類，然後你可以使用：

$park = new Park(/* your values to initialize the object */); 
echo json_encode($park->toArray()); 

Answer 3

我覺得你需要暴露私有財產做了一個設計錯誤值。

但是當然有一些情況應該這樣做。 正如PHP Object To JSON format指出的那樣，這樣做的一種方式將是低谷反思。

下面是使用PHP ReflectionClass來實現你想要的一個簡單的例子：

function getJson($object) 
{ 
    $result = array(); 
    $refl = new ReflectionClass($object); 
    foreach ($refl->getProperties() as $prop) { 
     $prop->setAccessible(true); 
     $result[$prop->name] = $prop->getValue($object); 
    } 
    return json_encode($result); 
}