識別事實表中的百分比

Question

我是編程新手，無法找到答案。

我有以下尺寸（表）和事實表：

• 客戶：客戶編號，HomeRegion
• 地區：RegionId，RegionName
• 數值指明MyTime：ID ，MyHour
• 事實表：客戶編號，RegionId，TIMEID，FactId

我必須報告：HomeRegion，小時，RegionName，UserPercentage。

如示例所示，只有3.67％的人，其家庭區域爲一個轉會乙上午9點等等。

我應該創建一個相似的。

問題是獲得UserPercentage。這是我迄今爲止所做的代碼。

SELECT c.HomeRegion, mt.myhour as Time, r.RegionName as CurrentRegion, 
(SELECT COUNT(*) 
     /*number of users who move from their home 
     region to CurrentRegion at specific time*/ 
)/COUNT(c.CustomerId)*100 as UserPercentage 
FROM dbo.FactTable ft 
inner join dbo.Customer c 
    ON ft.CustomerId = c.CustomerId 
inner join dbo.myTime mt 
    ON ft.TimeId = mt.ID 
inner join dbo.Regions r 
    ON ft.RegionId = r.RegionId 
WHERE mt.myhour = '09' 
GROUP BY c.HomeRegion, mt.myhour, r.RegionName 
ORDER BY c.HomeRegion, r.RegionName 

Answer 1

使用分析功能
*無需選擇或GROUPBY myHour不斷
*假設一個客戶應位於1個區一次（如果不是 - 這將是更難選擇）

select HomeRegion, CurrentRegion, 
count(*)/count(*) over() as overall_share, 
count(*)/count(*) over (partition by HomeRegion) as homeregion_share, 
    from 
    (SELECT c.HomeRegion, r.RegionName as CurrentRegion, c.CustomerId as CUST 
    FROM dbo.FactTable ft 
    inner join dbo.Customer c 
     ON ft.CustomerId = c.CustomerId 
    inner join dbo.myTime mt 
     ON ft.TimeId = mt.ID 
    inner join dbo.Regions r 
     ON ft.RegionId = r.RegionId 
    WHERE mt.myhour = '09' 
    GROUP BY c.HomeRegion, r.RegionName, c.CustomerId) uni_users 
    GROUP by HomeRegion, CurrentRegion 

Answer 2

在您的評論區嘗試這樣的內容。

SELECT (TMP1.Count*100)/COUNT(TMP2.CustomerId) AS 'Percentage' 
FROM 
(
SELECT COUNT(*) AS 'Count' 
FROM dbo.FactTable ft 
inner join dbo.Customer c ON ft.CustomerId = c.CustomerId 
inner join dbo.Regions r ON ft.RegionId = r.RegionId 
WHERE 
r.RegionName IN ('A','B','C','D','E') AND 
c.HomeRegion IN ('A','B','C','D','E') 
) AS 'TMP1', dbo.Customer AS 'TMP2'