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有人可以幫助下面的代碼。我試圖創建一個註冊查詢,但是當它被提交,我得到一個錯誤的下面一行:SQL第一項沒有添加到數據庫中
$insert_query = "insert into members (First_name, last_name, Address_1, Address_2, Postcode, Email, Membership_Number, Password) values('$fname','$lname','$address1','$address2','$postcode','$email','$member','$password')";
這僅影響FIRST_NAME,因爲其他字段名成功提交。
您的幫助將不勝感激!
<?php
$con = mysql_connect("localhost","root","") or die(mysql_error());
$select_db = mysql_select_db("thistlehc",$con);
if(isset($_POST['register']))
$fname = mysql_real_escape_string($_POST['fname']);
$lname = mysql_real_escape_string($_POST['lname']);
$address1 = mysql_real_escape_string($_POST['address1']);
$address2 = mysql_real_escape_string($_POST['address2']);
$postcode = mysql_real_escape_string($_POST['postcode']);
$email = mysql_real_escape_string($_POST['email']);
$member = mysql_real_escape_string($_POST['member']);
$password = mysql_real_escape_string($_POST['password']);
$query = "select membership_number from members where membership_number='$member'";
$link = mysql_query($query)or die(mysql_error());
$num = mysql_num_rows($link);
if ($num>0){
echo 'Membership Number already exists'; //Membership number already taken
}
else {
$insert_query = "insert into members (First_name, last_name, Address_1, Address_2, Postcode, Email, Membership_Number, Password) values('$fname','$lname','$address1','$address2','$postcode','$email','$member','$password')";
$result = mysql_query($insert_query)or die(mysql_error());
echo "Registered Successfully!";
}
?>
什麼錯誤,你得到?你可以把它添加到你的文章? – Lix
'注意:未定義的變量:第24行的Send_user_details.php中的fname 這就是上面顯示的行 –
你的$ fname變成null類型,所以在mysql中它變成空白值 – kirugan