幫助有需要的鐵血陣列，獲得IQueryable的結果到一個數組

有誰知道我能得到我的結果目前在QRY的IQueryable對象爲格式交錯數組：幫助有需要的鐵血陣列，獲得IQueryable的結果到一個數組

 series: 
      [{ 
       name: '2', 
       data: [0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0] 
        }, { 
       name: '3', 
       data: [1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 3, 0] 

       }]

我的問題是我的代碼目前所面對的環繞在12元數據部分的雙引號，也就是它看起來像這樣在客戶端上的調試器：

導致[0] {...} [0]：「2」 [1]：「[0,0,0,0,0,0,1,0,0,0,0,0]」？結果[1] {...} [0]：「3」 [1]：「[1,0,0,0,0,0,0,0,0,0,0,0]」

問題是我的數組包含一個單一的字符串元素，而不是一個12個數字的數組。

這裏是目前返回12號部分爲一個大的字符串我控制器代碼：

 var qry = from i in _db.Complaints 
      where i.Site.SiteDescription.Contains(searchTextSite) 
        && (i.Raised >= startDate && i.Raised <= endDate) 
      group i by i.ComplaintNatureTypeId.ToString() 
      into grp select new 
      { 
       Type = grp.Key, 
       Count = "[" + grp.Where(c => c.Raised.Month == 1).Count() + "," + 
         grp.Where(c => c.Raised.Month == 2).Count() + "," + 
         grp.Where(c => c.Raised.Month == 3).Count() + "," + 
         grp.Where(c => c.Raised.Month == 4).Count() + "," + 
         grp.Where(c => c.Raised.Month == 5).Count() + "," + 
         grp.Where(c => c.Raised.Month == 6).Count() + "," + 
         grp.Where(c => c.Raised.Month == 7).Count() + "," + 
         grp.Where(c => c.Raised.Month == 8).Count() + "," + 
         grp.Where(c => c.Raised.Month == 9).Count() + "," + 
         grp.Where(c => c.Raised.Month == 10).Count() + "," + 
         grp.Where(c => c.Raised.Month == 11).Count() + "," + 
         grp.Where(c => c.Raised.Month == 12).Count() + "]" 

      }; 


     return Json(qry.ToArray(), JsonRequestBehavior.AllowGet);

來源

2011-07-26 John

我想我需要創建一個數組和循環QRY對象，但問題是12個數字的排列是一個字符串。與此聯繫在一起的人提出了一種方法，非常感謝 – John

您需要傳遞一個對象，並且Json會將其序列化爲JSON字符串。

Count = new int[] { 
    grp.Where(c => c.Raised.Month == 1).Count(), 
    grp.Where(c => c.Raised.Month == 2).Count(), 
    grp.Where(c => c.Raised.Month == 3).Count(), 
    grp.Where(c => c.Raised.Month == 4).Count(), 
    grp.Where(c => c.Raised.Month == 5).Count(), 
    grp.Where(c => c.Raised.Month == 6).Count(), 
    grp.Where(c => c.Raised.Month == 7).Count(), 
    grp.Where(c => c.Raised.Month == 8).Count(), 
    grp.Where(c => c.Raised.Month == 9).Count(), 
    grp.Where(c => c.Raised.Month == 10).Count(), 
    grp.Where(c => c.Raised.Month == 11).Count(), 
    grp.Where(c => c.Raised.Month == 12).Count() 
}

或者你可以這樣做：

Count = Enumerable.Range(1, 12).Select(x => grp.Where(c => c.Raised.Month == x).Count())

來源

2011-07-26 08:34:52

您所創建的計數屬性爲一個字符串，它不應該是一個數組：

Count = new [] { 
grp.Where(c => c.Raised.Month == 1).Count(), 
grp.Where(c => c.Raised.Month == 2).Count(), 
... 
grp.Where(c => c.Raised.Month == 12).Count() 
}

來源

2011-07-26 08:32:49

幫助有需要的鐵血陣列，獲得IQueryable的結果到一個數組

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