迭代泛型類型<User> ArrayList

Question

我想從arraylist中獲取值。

我有如下的用戶類型bean類..

class User{ 

     public String link; 
     public String url; 

    User(String l,String u){ 
      this.link=link; 
      this.url=url; 
     } 
setters and getters below.. 

在這裏，我試圖寫有主要的類。

public class ListClass{ 
     public static void main(String args[]){ 
      List<User> list = new ArrayList<User>(); 
      list.add(new User("link1","url1")); 
      list.add(new User("link2","url2")); 
      list.add(new User("link3","url3")); 

      //here i want to iterate both links and urls one by one 

      Iterator it=list.iterator(); 
      // remaining the code to get both link1 and url1 .. 
} 

我需要的輸出：

link1 url1 
link2 url2 
link3 url2 

Answer 1

可以使用換的結構，而不是迭代器：

for (User u : list) { 
    System.out.println(u.link + " " + u.url); 
} 

如果你一定要使用迭代器：

Iterator<User> it=list.iterator(); 
while (it.hasNext()) { 
    User u = it.next(); 
    System.out.println(u.link + " " + u.url); 
} 

Answer 2

for (User u : list) { 
    System.out.println(u.getLink() + " " + u.getUrl()); 
} 

Answer 3

如果你堅持用itereator：

Iterator<User> it = list.iterator(); 
while(it.hasNext()) { 
    /... 
    it.next(); 
} 

Answer 4

正如已經被你可以使用enhanced for statement其他用戶說。考慮還加入了toString()實施User：

class User 
{ 
    @Override public String toString() 
    { 
     return this.link + " " + this.url; 
    } 
} 

這將減少環路：

for (User u: list) 
{ 
    System.out.println(u); 
}