在php中顯示基於當前日期的日期

Question

我使用以下代碼來顯示基於當天的日期，即如果今天是星期一或星期二，它應該顯示下一個星期三日期，如果有其他日期，它應該顯示下一個星期一日期。

下面是代碼：

<?php 
    $date = str_replace("/", "-", $date); 
    $nextWed = date("l jS F, Y",strtotime('next wednesday')); 
    $nextMon = date("l jS F, Y",strtotime('next monday')); 

if(date('D', $timestamp) === 'Mon' or date('D', $timestamp) === 'Tue'){ 

echo '<div class="time-note">Order your box before Tuesday 11.59pm and get it delivered on '.$nextWed .'</div>';} 
else { 
    echo '<div class="time-note">Order your box before Sunday 11.59pm and get it delivered on '.$nextMon.'</div>';}?> 

如果我查看了今天就把它仍然呼應Order your box before Sunday 11.59pm and get it delivered on Monday 19th October 2015。而應該說Order your box before Tuesday 11.59pm and get it delivered on Monday 14th October 2015

Answer 1

你唯一缺少的是$timestamp

添加此行$timestamp = time();正下方$nextMon = date("l jS F, Y",strtotime('next monday'));

編碼快樂！

Answer 2

改變這一行

if(date('D') === 'Mon' or date('D') === 'Tue')