貸款計算器更改

我創建了一個計算貸款的程序，但它並沒有按照我的教授提出的要求進行。可以讓我看到正確的改動。源代碼將會很棒並且節省時間，但是你不需要。貸款計算器更改

繼承人的問題：

寫一個程序，讓用戶在號碼中輸入的年貸款額度和貸款期限，並顯示開始從5％至8％的每個利率每月支付的價款，增加1/8。繼承人樣品運行：

Loan amount: 10000 [Enter] 
Numbers of Years: 5: [Enter] 

Interest rate   Monthly Payment      Total Payment 
5%       188.71        11322.74 
5.125%      189.28        11357.13

繼承人我以前的代碼：

# include <iostream> 
# include <iomanip> 
# include <cmath> 

using namespace std; 

int main() 
{ 
    double loanAmountA; 
    double annualRate; 
    double paymentAmount; 
    double amountInterest; 
    double ratePeriod; 
    double balanceAfter; 
    double amountApplied; 
    double balance; 
    double paymentPeriod; 
    int paymentsPerYear; 
    int totalPayments; 
    int loanCount = 1; 
    int paymentCount = 1; 
    bool anotherLoan = true; 
    char response; 

    while (anotherLoan == true) 
    { 
     cout<<"Enter amount of loan A:$ "; 
     cin>>loanAmountA; 
     cout<<endl; 
     cout<<"Enter annual percentage rate (APR): "<<"%"; 
     cin>>annualRate; 
     cout<<endl; 
     cout<<"Enter the number of payments per year: "; 
     cin>>paymentsPerYear; 
     cout<<endl; 
     cout<<"Enter the total number of payments: "; 
     cin>>totalPayments; 
     cout<<endl; 
     cout<<"Payment Payment Amount Amount to Balance after"; 
     cout<<endl; 
     cout<<"Number Amount Interest Principal This Payment"; 
     cout<<endl; 

     cin.ignore(80,'\n'); 

     while (paymentCount <=totalPayments) 
     { 
      annualRate = annualRate/100; 
      balance = loanAmountA - totalPayments * paymentAmount; 
      ratePeriod = balance * annualRate; 
      paymentAmount = loanAmountA * (totalPayments/paymentsPerYear * annualRate)/totalPayments; 
      balanceAfter = balance - paymentAmount; 
      balance = loanAmountA - (paymentCount * paymentAmount); 


      cout<<left<<setprecision(0)<<setw(3)<<paymentCount; 
      cout<<setw(13)<<left<<fixed<<setprecision(2)<<paymentAmount; 
      cout<<setw(26)<<left<<fixed<<setprecision(2)<<ratePeriod; 
      cout<<setw(39)<<left<<fixed<<setprecision(2)<<balance; 
      cout<<setw(42)<<left<<fixed<<setprecision(2)<<balanceAfter; 

      if (paymentCount % 12 == 0) 
      { 
       cout<<endl; 
       cout<<"Hit <Enter> to continue: "<<endl; 
       cin.ignore(80,'\n'); 
       cin.get(); 
      } 
      paymentCount++; 
      loanCount++; 
      cout<<endl; 
     } 

     cout<<"Would you like to calculate another loan? y/n and <enter>"; 
     cin>>response; 
     if (response == 'n') 
     { 
      anotherLoan = false; 
      cout<<endl<<endl; 
      cout<<"There were"<<loanCount<< "loans processed."; 
      cout<<endl<<endl; 
     } 
    } 
    return 0; 
}

來源

2010-07-25 John

您必須改進格式。當你編輯這個問題時，玩一下可用的東西。 – 2010-07-25 14:56:59

這不符合教授的指導原則？你從來沒有告訴我們你要解決什麼問題。 – 2010-07-25 15:22:15

哦，爲什麼作業的作業比典型的真實世界編程任務/錯誤更有趣？ – 2010-07-25 15:48:41

你嘗試使用調試器，並找到故障點？

來源

2010-07-25 14:59:33

對於Linux，有'ddd'，這很酷。 – 2010-07-25 15:49:08

貸款計算器更改

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