2017-10-28 56 views
0

如何通過實例化一個類創建的對象與由JSON反序列化(JsonConvert)創建的動態對象之間的映射考慮到我不知道動態對象的字段?換句話說,我想更新按名稱匹配的動態對象字段。JSON反序列化後對象與動態創建的對象之間的映射

這是我的示例代碼:

string json = {\"NDG\":7803, \"NumberOfNights\":2, \"Nome\":\"Ago\", \"Cognome\":\"Mar\", \"CognomeNome\":\"\"}; 
string djson = ?? //I don't know the structure coming from a call as parameter but I know there are some json string identical fields 

public class myVars 
{ 
    public string Userid { get; set; } 
    public string Nome { get; set; } 
    public string Cognome { get; set; } 
    public string CognomeNome { get; set; } 
} 

myVars object1 = JsonConvert.DeserializeObject<myVars>(json); 
dynamic object2 = JObject.Parse(djson); // object2 contains a field named "CognomeNome" 


myVars.CognomeNome = myVars.Cognome + myVarsNome; 
MapObjects(object1 , object2); 
string rjson = JsonConvert.SerializeObject(object2); //returns {"CognomeNome":""} 

public static object MapObjects(object source, object target) 
    { 
     foreach (PropertyInfo sourceProp in source.GetType().GetProperties()) 
     { 
      PropertyInfo targetProp = target.GetType().GetProperties().Where(p => p.Name == sourceProp.Name).FirstOrDefault(); 
      if (targetProp != null && targetProp.GetType().Name == sourceProp.GetType().Name) 
      { 
       targetProp.SetValue(target, sourceProp.GetValue(source)); 
      } 
     } 
     return target; 
    } 
+2

你到目前爲止嘗試過什麼? –

+3

您需要爲您的問題添加更多信息才能負責(例如,也許?)。看起來['AutoMapper'支持](https://github.com/AutoMapper/AutoMapper/wiki/Dynamic-and-ExpandoObject-Mapping)for'dynamic',所以這大概延伸到'JObject' – StuartLC

+0

可能的重複[如何從一個靜態對象創建一個動態對象?](https://stackoverflow.com/questions/23156815/c-sharp-how-to-create-a-dynamic-object-from-a-static-object ) – derloopkat

回答