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我被困在一個非常基本的sql查詢腳本中。有人會注意到我無法看到的東西。我已經檢查了SQL查詢工作正常時,它是從中mysqladmin執行:PHP錯誤mysql_fetch_array():提供的參數不是有效的MySQL結果資源
<?
include ('gps_db_connect.php');
$query = "SELECT * from gps WHERE server_time > '20130124'";
echo $query;
$result = mysqli_query($connection, $query) or die(' Error getting data');
echo ' After query';
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo $row['server_time'];
}
?>
這裏是屏幕顯示/輸出:
SELECT * from gps WHERE server_time > '20130124' After
query
PHP Error Message
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/a9440109/public_html/test.php on line 7
看看你的right - > –