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只有我上課的第三週（新編程）。 我正在用Java編寫一個基於文本的故事，但我在這個過程中遇到了一個問題。我有一個名爲「static String dogName;」的靜態變量我試圖改變（只有一次）的價值。在比賽開始時，用戶可以選擇給他們的狗命名。當我嘗試命名狗時，由於靜態字符串dogName，代碼會跳過命名提示。在JAVA中將非靜態變量轉換爲靜態？
- 我想給用戶選擇他們的狗的名字。
- 如果在我的代碼中有更好的方法來做事情，請告訴我。代碼
部分可能不完全一樣的決定......
public static Scanner keyboard = new Scanner(System.in);
public static int choice;
// dogName is Dogs name forever a hundred times rick & morty
static String dogName;
public static void main(String[] args) {
int karma = 0;
// Dog stuff...
Dog Dandy;
Dandy = new Dog();
// Prologue
System.out.println("You're walking through an alley late at night "
+ ", you see a stray dog. What do you do? ");
System.out.println("[1] Approach");
System.out.println("[2] Attempt to touch");
System.out.println("[3] Give treat");
boolean running = true;
GAME:
while (running) {
choice = keyboard.nextInt();
switch (choice) {
case 1:
System.out.println("The dog became alarmed!");
Dandy.bark();
break;
case 2:
System.out.println("The dog becomes aggressive!");
Dandy.bite();
break;
case 3:
System.out.println("The dog comes in peace");
Dandy.sit();
break;
}
if (choice == 1) {
System.out.println("You stand back in caution. You cannot risk being bitten.");
}
if (choice == 2) {
System.out.print("");
karma--;
}
if (choice == 3) {
System.out.println("You give the dog a treat. It wags its tail in excitement");
karma++;
}
// Chapter 1.1 - Man's best friend
System.out.println("\nThe dog will live a harsh life in the outside world. What would you like to do? "
+ "\n[1] Adopt dog\n[2] Leave dog\n[3] Quit game! You're bored...");
choice = keyboard.nextInt();
switch (choice) {
case 1:
System.out.println("\nYou welcome your new companion");
System.out.println("\nWould you like to give him a name?\n[1] No\n[2] Yes");
choice = keyboard.nextInt();
switch (choice){
case 1:
System.out.println("You see a shiny object beneath his foot, it's a dog collar."
+ "\nYou pick up the dog collar and see the name Todd on it."
+ "\nYes, because you did not choose a name for your dog, we gave him the most basic name ever. "
+ "You're welcome.");
dogName = "Todd"; //RIP doge
karma--;
break;
case 2:
dogName = keyboard.nextLine();
karma++;
}
}
// Good guy player gives his dog a name
// Chapter 1.2 - Home sweet home
System.out.println("\n" + dogName + " crawls up to your leg and lets out a whimper.\n"
+ "Is " + dogName + " just afraid of the dark, or is he hungry?"
+ "\nYou don't know the last time he ate. What will you do?");
System.out.println("\n[1] Go home\n[2] Find a store\n[3] Search the area");
choice = keyboard.nextInt();
if (choice == 1){
System.out.println("\nYou head home with " + dogName + " as fast as you can.\n"
+"On the way back, " + dogName + " seems extremely happy to be with"
+ " his new owner.\nGoing out you had no idea you'd bring home a new friend.");
karma++;
}
if (choice == 2){
System.out.println("");
System.out.println("");
}
if (choice == 3){
}
}
// GAME ENDING
if (karma > 0) {
System.out.println("\nYou ended with " + karma + " karma. Good job!");
}
else if (karma == 0){
System.out.println("\nYou ended with " + karma + " karma. Neither good nor bad, a neutral state.");
}else{
System.out.println("\nYou ended with " + karma + " karma. Bad job!");
}
// CREDITS
System.out.println("\n\t# THANK YOU FOR PLAYING #");
System.out.println("\t# Game created by aliens from outer space #");
}
}
有了這篇文章，我想感謝所有幫助我的人，他們給了我建議並向我介紹新的做事方式。在您的幫助下，我修復了我的錯誤，並且我也在學習如何將所有內容連接到彼此，以便下次我的代碼更加高效。當我回到課堂時，不能等待展示我的同學:)。 –