問題，同時將xsd轉換爲Java POJO當屬性名稱=「值」時

Question

如何將下面的一段xsd轉換爲java pojo。我嘗試使用JAXB項目方式使用eclipse轉換它，但它給我錯誤（Property "Value" is already defined. Use <jaxb:property> to resolve this conflict.）。我認爲它是因爲我有名稱=「價值」，並在某處發生衝突。

<xs:complexType name="demo"> 
    <xs:simpleContent> 
     <xs:extension base="xs:string"> 
     <xs:attribute name="value" type="xs:string" /> 
     </xs:extension> 
    </xs:simpleContent> 
    </xs:complexType> 

幫助表示讚賞！

Answer 1

表示複雜類型的Java類可能是這樣的：

@XmlType(name = "demo") 
public class Demo { 
    private String valueAttr; 
    private String valueContent; 

    @XmlAttribute(name = "value") 
    public String getValueAttr() { 
     return this.valueAttr; 
    } 

    public void setValueAttr(String valueAttr) { 
     this.valueAttr = valueAttr; 
    } 

    @XmlValue 
    public String getValueContent() { 
     return this.valueContent; 
    } 

    public void setValueContent(String valueContent) { 
     this.valueContent = valueContent; 
    } 

} 

類名，字段名，和任何你想他們是方法的名稱可以改變，因爲XML名稱在註釋中明確給出。

要看到它的工作，使用：

@XmlRootElement 
public class Test { 

    @XmlElement 
    private Demo demo; 

    public static void main(String[] args) throws Exception { 
     Demo demo = new Demo(); 
     demo.setValueAttr("this is the attr value"); 
     demo.setValueContent("this is the element content"); 
     Test test = new Test(); 
     test.demo = demo; 

     JAXBContext jaxbContext = JAXBContext.newInstance(Test.class); 
     Marshaller marshaller = jaxbContext.createMarshaller(); 
     marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); 
     marshaller.marshal(test, System.out); 
    } 
} 

輸出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> 
<test> 
    <demo value="this is the attr value">this is the element content</demo> 
</test>