MySQL布爾全文搜索子表達式

我想在MySQL中編寫一個布爾全文搜索查詢。但我想有順序的結果：（>意味着更高）MySQL布爾全文搜索子表達式

Exact Matches>Including all the words>Including some of the words

用下面的查詢，我得到確切匹配更高：

SELECT *, MATCH(name,description,address) 
AGAINST('>("word1 word2 word3") <(word1 word2 word3)' IN BOOLEAN MODE) 
AS score FROM samples WHERE MATCH(name,description,address) 
AGAINST('>("word1 word2 word3") <(word1 word2 word3)' IN BOOLEAN MODE) ORDER BY score DESC

通過以下查詢，我得到的文檔包含的所有單詞都高於包含查詢部分內容的單詞：

SELECT *, MATCH(name,description,address) 
AGAINST('>(+word1 +word2 +word3) <(word1 word2 word3)' IN BOOLEAN MODE) 
AS score FROM samples WHERE MATCH(name,description,address) 
AGAINST('>(+word1 +word2 +word3) <(word1 word2 word3)' IN BOOLEAN MODE) ORDER BY score DESC

但我想結合這兩個查詢。這是迄今爲止最好的，但我沒有得到我想要的結果。

SELECT *, MATCH(name,description,address) 
AGAINST('>("word1 word2 word3") <(>(+word1 +word2 +word3) <(word1 word2 word3))' IN BOOLEAN MODE) 
AS score FROM samples WHERE MATCH(name,description,address) 
AGAINST('>("word1 word2 word3") <(>(+word1 +word2 +word3) <(word1 word2 word3))' IN BOOLEAN MODE) 
ORDER BY score DESC

有沒有辦法做到這一點沒有UNIONs？

來源

2015-12-30 Aidin

如果有超過2個單詞匹配像'match（..）against（'> frist second''），沒有辦法做到這一點。你可能不得不使用'union'。 –

這項工作？

SELECT *, 
     MATCH (name,description,address) 
      AGAINST ('"word1 word2 word3"' IN BOOLEAN MODE) score_exact, 
     MATCH (name,description,address) 
      AGAINST ('+word1 +word2 +word3' IN BOOLEAN MODE) score_all, 
     MATCH (name,description,address) 
      AGAINST ('word1 word2 word3' IN BOOLEAN MODE) score_some 
    FROM samples 
    WHERE MATCH (name,description,address) 
      AGAINST ('word1 word2 word3' IN BOOLEAN MODE) 
ORDER BY score_exact DESC, score_all DESC, score_some DESC

來源

2016-01-07 16:56:46 Arth

哇很有創意！我認爲它會起作用，我要測試它。 – Aidin

(SELECT *, 
     1 AS sort_order,  -- top priority to exact match 
     1.0 AS extra_ordering 
     ... WHERE txt = 'aaaa bbbb cccc') 
UNION ALL 
(SELECT *, 
     2 AS sort_order,  -- next to all words exist 
     MATCH(txt) AGAINST("+aaaa +bbbb +cccc" IN BOOLEAN MODE) 
     ... WHERE MATCH(txt) AGAINST("+aaaa +bbbb +cccc" IN BOOLEAN MODE) 
UNION ALL 
(SELECT *, 
     3 AS sort_order,  -- finally "any" words 
     MATCH(txt) AGAINST("aaaa bbbb cccc" IN BOOLEAN MODE) 
     ... WHERE MATCH(txt) AGAINST("aaaa bbbb cccc" IN BOOLEAN MODE) 
ORDER BY sort_order ASC, extra_ordering DESC 
LIMIT 1; -- to get the 'best'

來源

2016-01-06 23:57:56

我與工會的問題是它會返回重複的記錄，因爲雖然主鍵相同，但分數列是不同的！ – Aidin

因爲我添加的列，不會有任何重複：'sort_order'。我添加了「LIMIT 1」。 –

我必須得到更多結果，並且如果一行出現在多個子查詢中，它將被複制，那麼對於每個子查詢，排序順序是不同的。 – Aidin

MySQL布爾全文搜索子表達式

回答

相關問題