SQL子查詢疑問

我有點卡住，並希望得到幫助.....我敢肯定，我需要使用子查詢，但是當我嘗試即時獲取錯誤說，返回多個行... 。SQL子查詢疑問

所以這是代碼

SELECT to_char(p.releasedate, 'YYYY') AS releaseyear , t.genre 
, COUNT(*) AS "Number of awards" 
FROM dbf11.film p 
JOIN dbf11.genre t 
ON p.filmID = t.filmID 
GROUP BY p.releasedate, t.genre 
ORDER BY p.releasedate, t.genre ;

我想要做的是....每年顯示無。電影每個流派的

什麼我目前得到的是

2010 Action 1 
2010 Comedy 1 
2010 Comedy 1 
2011 Action 1 
2011 Action 1 
2011 Action 1

我想要它顯示的

2010 Action 1 
2010 Comedy 2 
2011 Action 3

來源

2011-06-01 John

你能發佈您試圖使用的子查詢？ – 2011-06-01 16:29:04

SELECT to_char(p.releasedate, 'YYYY') AS releaseyear, 
    t.genre. 
    COUNT(*) AS "Number of awards" 
FROM dbf11.film p 
INNER JOIN dbf11.genre t ON p.filmID = t.filmID 
GROUP BY to_char(p.releasedate, 'YYYY'), t.genre 
HAVING COUNT(*) > 1 
ORDER BY to_char(p.releasedate, 'YYYY'), t.genre;

來源

2011-06-01 16:28:25 RedFilter

另一件事...如果我想只顯示具有更多1釋放的流派，怎麼辦...... – John 2011-06-01 16:30:21

@John看到我的更新，你可以使用'HAVING'子句 – RedFilter 2011-06-01 16:35:37

謝謝....我忘了數數。 ...我一直試着用count（*）> 1 ..... – John 2011-06-01 16:37:16

試試這個

SELECT to_char(p.releasedate, 'YYYY') AS releaseyear , t.genre 
, COUNT(*) AS "Number of awards" 
FROM dbf11.film p 
JOIN dbf11.genre t 
ON p.filmID = t.filmID 
GROUP BY to_char(p.releasedate, 'YYYY'), t.genre 
ORDER BY releaseyear, t.genre

來源

2011-06-01 16:29:28 cordsen

SQL子查詢疑問

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