從PHP中的MySQL數據創建表

Question

我想做一個項目，其中它顯示3前一個月和當前月..現在我的問題是我不知道在哪裏或如何反映這個MySQL數據到一個表中的PHP ...任何人都可以教我嗎？

請原諒我，如果我不給你解釋系統好，因爲我只是一個努力的程序員..

這應該是表將如何看起來像： http://www.fileden.com/files/2011/7/27/3174077//1.JPG

這裏是PHP代碼和MySQL查詢，我要投入到一個表：

<form action="" method="post" class="niceform"> 
<fieldset> 
    <legend>Job Orders</legend>\ 
    <table> 
<tr> 
<th>SSA</th> 
<th>Months</th> 
</tr> 

     <?php 

$datefrom= $_POST['timestamp']; 
$dateto=$_POST['timestamp1']; 

$parsemonth=""; 
$parseday ="01"; 

$conditionmonth=$parsemonth-3; 


//january 
if ($conditionmonth == '1'){ 

$sql="SELECT 
a.specialist_partner_ID 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-01-01', INTERVAL 3 MONTH) and   DATE_SUB('2011-09-30', INTERVAL 3 MONTH) THEN a.job_order_number ELSE null END) As December, 
count(CASE WHEN a.receivedDate between DATE_SUB('2011-01-01', INTERVAL 2 MONTH) and DATE_SUB('2011-09-30', INTERVAL 2 MONTH) THEN a.job_order_number ELSE null END) As November 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-01-01', INTERVAL 1 MONTH) and DATE_SUB('2011-09-30', INTERVAL 1 MONTH) THEN a.job_order_number ELSE null END) As October 
,count(CASE WHEN a.receivedDate between '2011-01-01' and '2011-01-30'THEN a.job_order_number ELSE null END) As Jauary 
,count(job_order_number) As Total 
FROM jo_partner a 
WHERE a.receivedDate BETWEEN '2011-01-01' AND '2011-12-31' 
GROUP BY a.specialist_partner_ID"; 
} 

//february 
else if ($conditionmonth == '2'){ 

$sql="SELECT 
a.specialist_partner_ID 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-02-01', INTERVAL 11 MONTH) and DATE_SUB('2011-02-29', INTERVAL 3 MONTH) THEN a.job_order_number ELSE null END) As November 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-02-01', INTERVAL 10 MONTH) and DATE_SUB('2011-02-29', INTERVAL 2 MONTH) THEN a.job_order_number ELSE null END) As December 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-02-01', INTERVAL 9 MONTH) and DATE_SUB('2011-02-29', INTERVAL 1 MONTH) THEN a.job_order_number ELSE null END) As January 
,count(CASE WHEN a.receivedDate between '2011-02-01' and '2011-02-29'THEN a.job_order_number ELSE null END) As February 
,count(job_order_number) As Total 
FROM jo_partner a 
WHERE a.receivedDate BETWEEN '2011-01-01' AND '2011-12-31' 
GROUP BY a.specialist_partner_ID"; 
} 

//march 
else if ($conditionmonth == '3') 
{ 

$sql="SELECT 
a.specialist_partner_ID 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-03-01', INTERVAL 3 MONTH) and  DATE_SUB('2011-03-31', INTERVAL 3 MONTH) THEN a.job_order_number ELSE null END) As December 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-03-01', INTERVAL 2 MONTH) and DATE_SUB('2011-03-31', INTERVAL 2 MONTH) THEN a.job_order_number ELSE null END) As Jauary 
,count(CASE WHEN a.receivedDate between DATE_SUB('2011-03-01', INTERVAL 1 MONTH) and DATE_SUB('2011-03-31', INTERVAL 1 MONTH) THEN a.job_order_number ELSE null END) As February 
,count(CASE WHEN a.receivedDate between '2011-03-01' and '2011-03-31'THEN a.job_order_number ELSE null END) As March 
,count(job_order_number) As Total 
FROM jo_partner a 
WHERE a.receivedDate BETWEEN '2011-01-01' AND '2011-12-31' 
GROUP BY a.specialist_partner_ID"; 
} 

等等等等...直至十二月

while ($row = mysql_fetch_row($sql) 
{ 

} 
?> 
    </tr></table> 
</fieldset> 

的情況是，當我選擇月份可查看該月的報告中，前一月，一月只有數據纔可以看到最後3 consrctive月，前月和十一月

Answer 1

鑑於表是建立使用該類型的數據：

<tr> 
    <td>item1</td> 
    <td>item2</td> 
</tr> 

這是非常簡單的使用SQL建表，只是用表標籤括號中的數據：

SQL代碼只，不推薦，因爲它留下一個XSS安全漏洞！
只有當你是100％肯定你的數據庫裏面的數據是安全的

/*escape all data coming from a user */ 
/*or even better just escape all incoming data *period* */ 
$SSAID = mysql_real_escape_string($_SESSION['SESS_SSA_ID']); 

/*don't use 2 queries if you can do it in one */ 
$result = mysql_query("SELECT CONCAT('<tr>',GROUP_CONCAT(
           CONCAT('<td>',ug.group_name,</td>), SEPARATOR ' ') 
           ,'</tr>') as tablestring 
         FROM user_group ug 
         INNER JOIN user u ON (ug.usr_group_ID = u.user_group_id) 
         WHERE u.SSA_ID = ''$SSAID')"; 

$row = mysql_fetch_row($result); 
echo "here comes the table"; 
echo $row['tablestring']; 

此代碼構造整個表中的SQL使用。的另一種選擇是循環儘管值和拼湊表在while循環：

使用while循環代碼示例中，脫輸出，防止XSS

$result = mysql_query("SELECT ug.group_name 
         FROM user_group ug 
         INNER JOIN user u ON (ug.usr_group_ID = u.user_group_id) 
         WHERE u.SSA_ID = ''$SSAID')"; 
$table = "<tr>"; 
while ($row = mysql_fetch_row($result)); 
{ 
    $table .= "<td>".htmlspecialchars($row['group_name'], ENT_QUOTES, 'UTF-8')."</td>"; 
} 
$table .= "</tr>"; 
echo "here comes the table"; 
echo $table; 

要記住的要點

• 使用mysql_real_escape_string()將所有$vars注入到SQL語句中。
• 總是使用htmlspecialchars()轉義回顯到屏幕上的數據來防止XSS。
• 擺脫select *的習慣，只選擇你需要的東西。
• 請勿使用兩個查詢並使用php作爲它們之間的信使，請改爲使用一個查詢，參閱關於SQL聯接的教程。

鏈接
SQL注入：How does the SQL injection from the "Bobby Tables" XKCD comic work?
XSS預防：How to prevent XSS with HTML/PHP?
PHP-MySQL的教程：http://www.tizag.com/mysqlTutorial/
GROUP_CONCAT：http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat

Answer 2

我不知道我是否正確理解，但繼承我的嘗試。

其標題創建表：現在

<table> 
<tr> 
<th>Header 1</th> 
<th>Header 2</th> 
</tr> 

，你可以用你從你的MySQL查詢得到的數據填滿它。我不知道你的數據是如何構建的，但有一種方法可以這樣做：

<?php 
    foreach($groupName as $group){ 
     echo " 
      <tr> 
       <td>".$group->a."</td> 
       <td>".$group->b."</td> 
      </tr> 
     "; 
    } 
?> 

現在就關閉表格。

再一次，我不太瞭解你的目標是什麼，但我希望這有助於。

Answer 3

在第一個mysql查詢中應該有另一個WHERE子句來指定所需的日期。另外，正如評論中所建議的，您應該對來自用戶的所有數據使用mysql_real_escape_string（），以防止數據庫被黑客入侵。

如果你的表存儲與PHP運行時間）一個int（存儲時，你可以從現在（無論本月你選擇或）替代三個月，把它的查詢，如下所示：

$january = 1293840000; // january 1st 00:00 unix timestamp 
$SSAID = mysql_real_escape_string($SSAID); // injection.. 
$query = mysql_query("SELECT * FROM user WHERE SSA_ID = '$SSAID' AND timeAdded <= '$january'"); 

然後使用

while ($row = mysql_fetch_row($result) 
{ 

} 

和使用定界符遍歷數據所有你需要做的就是。例如

$html = <<<HTML 
<table> 
blahblah 
</table> 
HTML; 

希望這會有所幫助。將根據請求提供代碼，但這些建議應該足以生成你想要的內容。

編輯：

//looping through the mysql results and putting them in a table 
$tables = "<table>"; 
while ($row = mysql_fetch_row($result)) { 
    $tables .= "<tr>"; 
    foreach ($row as $key => $value) { 
     $tables .= <<<HTML 
     <td>$value</td> 
HTML; 
     } 
     $tables .= "</tr>"; 
} 

你能不能給我們的var_dump（$ mysql_fetch_assoc（$結果））;結果，因爲這會給我們一個什麼樣的查詢返回的結果的想法，所以我們可以提供一個準確的答案（代碼而）