選擇在自己的列中排列標準的語句

Question

這可能很簡單，但我已經搜索了文檔，並且找不到它。這裏的源表：

store item date  sales 
101 00001 27-Oct-12 1 
101 00002 27-Oct-12 0 
102 00001 27-Oct-12 2 
102 00002 27-Oct-12 1 
101 00001 3-Nov-12 0 
101 00002 3-Nov-12 0 
102 00001 3-Nov-12 1 
102 00002 3-Nov-12 1 

...我想寫一個查詢利用與具有自己的列，也就是說，只要項目＃賣場每月銷售的表落得00001--

monthyear store101sales otherstoresales 
10/2012 1    2 
11/2012 0    1 

下面是我tried--

select distinct 
    year(date) as SalesYear, 
    month(date) as SalesMonth, 
    sum(case when store in (101) then sales.count else 0 end) as store101sales, 
    sum(case when store in (102,103) then sales.count else 0 end) as otherstoresales, 
from source_table 
where item=00001; 
GROUP BY SalesYear, SalesMonth, store101sales, otherstoresales, 
ORDER BY SalesYear, SalesMonth, store101sales, otherstoresales; 

讚賞任何幫助的代碼;謝謝！

Answer 1

你接近，不需要GROUP BY聚集，並且不知道如果MySQL允許在GROUP BY或沒有使用別名：

select year(date) as SalesYear, 
    month(date) as SalesMonth, 
    sum(case when store in (101) then sales else 0 end) as store101sales, 
    sum(case when store in (102,103) then sales else 0 end) as otherstoresales 
from source_table 
where item=00001; 
GROUP BY year(date), month(date) 
ORDER BY SalesYear, SalesMonth, store101sales, otherstoresales;