SQL查詢最高3

Question

一個模式：

Cereal 
Cereal_name 
Buyer_name 

Cereal_name是穀物
Buyer_name的名字是誰帶來了一定的穀物

我試圖列出每個穀物和數字買家他們都買次，然後找到頂級的4穀物：例如一個答案是：

'HoneyNut' 400 
'Cap'n Crunch' 400 
'Chocolate Flakes' 300 
'Frosted Flakes' 200 

注：療法e爲4，因爲他們中的一個具有相同數量的

我有什麼是：

Select Cereal_name, count(*) as numOfCount 
From Cereal 
Group By numOfCount Desc 

我想用rowNum<=3但在這種情況下無法正常工作

提前感謝！

Answer 1

嘗試：

SELECT * FROM 
(SELECT 
    Cereal_name, 
    COUNT(*) as numOfCount 
FROM Cereal 
GROUP BY numOfCount 
ORDER BY COUNT(*) DESC 
) CEREALS 
WHERE ROWNUM <= 3 

我認爲甲骨文。

DB2：

也許這一點，但我不知道：

SELECT 
    Cereal_name, 
    COUNT(*) as numOfCount 
FROM Cereal 
GROUP BY numOfCount 
ORDER BY COUNT(*) DESC 
FETCH FIRST 3 ROWS ONLY 

Answer 2

如果你不能使用DB2的兼容模式，使用標準的ANSI SQL窗口函數應該讓你有：

 
select * 
from (
    select t1.*, 
     dense_rank() over (order by cereal_count) as rank 
    from (
    select cereal_name, 
      count(*) as cereal_count 
    from cereal 
    group by cereal_name 
) t1 
) t2 
where rank <= 3 
order by rank desc 

Answer 3

也許這樣？

SELECT G.Cereal_name, G.numOfCount 
FROM (
    Select Cereal_name, count(*) as numOfCount 
    From Cereal 
    Group By Cereal_name) G 
inner join (
    Select DISTINCT count(*) as numOfCount 
    From Cereal 
    Group By Cereal_name 
    order by numOfCount Desc 
    FETCH FIRST 3 ROWS ONLY) C on C.numOfCount = G.numOfCount 
order by G.numOfCount DESC