基於MySQL標籤的系統

我目前正在爲音樂網站編寫基本搜索系統，系統使用標籤（'Instrumental Duo'，'Instrumental Trio'，'latin'，..ect）進行搜索。我試圖找出如何使用標籤搜索MySQL數據庫來限制結果。基於MySQL標籤的系統

這些表的目的是相關的;

| Items |   | Tags  | 
|----------|   |----------| 
| PK_Items | One - Many | FK_Items | 
| Title |   | PK_Tags | 
| Writer |   | Tag_txt |

表中的每個項目項目將在表中的多個項目標籤

總之我希望能夠給數據庫的標籤集合，並將它歸還所有匹配

示例數據

的項代

該表已被使用

CREATE TABLE Items 
(
    PK_Items int NOT NULL AUTO_INCREMENT, 
    Title TEXT, 
    Writer varchar(30), 
    PRIMARY KEY(PK_Items) 
); 
CREATE TABLE Tags 
(
    PK_Tags int NOT NULL, 
    FK_Items int NOT NULL, 
    Tag_Txt varchar(100), 
    PRIMARY KEY(PK_Type), 
    FOREIGN KEY(FK_Items) REFERENCES Items(PK_Items) 
);

樣本數據

+----------+-------------+------------------+ 
| <b>PK_Items</b> | <b>Title</b>  | <b>Writer</b>   | 
+----------+-------------+------------------+ 
|  1 | Song1  | Joe Blogs  | 
+----------+-------------+------------------+ 
|  2 | Song2  | Joe Blogs  | 
+----------+-------------+------------------+ 
|  3 | Song3  | Jane Smith  | 
+----------+-------------+------------------+ 

+----------+-------------+------------------+ 
| <b>PK_Tags</b> | <b>FK_Items</b> | <b>Tag_Txt</b>   | 
+----------+-------------+------------------+ 
|  1 |   1 | Slow    | 
+----------+-------------+------------------+ 
|  2 |   1 | Jazz    | 
+----------+-------------+------------------+ 
|  3 |   2 | Fast    | 
+----------+-------------+------------------+ 
|  4 |   2 | Rock    | 
+----------+-------------+------------------+ 
|  5 |   3 | Slow    | 
+----------+-------------+------------------+ 
|  6 |   3 | Rock    | 
+----------+-------------+------------------+

創建如果我想搜索「慢」，我應該有與慢速標籤例如顯示所有項目

+----------+-------------+------------------+ 
| <b>PK_Items</b> | <b>Title</b>  | <b>Writer</b>   | 
+----------+-------------+------------------+ 
|  1 | Song1  | Joe Blogs  | 
+----------+-------------+------------------+ 
|  3 | Song3  | Jane Smith  | 
+----------+-------------+------------------+

或者，如果我搜索「慢」和「搖滾」，我會得到

+----------+-------------+------------------+ 
| <b>PK_Items</b> | <b>Title</b>  | <b>Writer</b>   | 
+----------+-------------+------------------+ 
|  3 | Song3  | Jane Smith  | 
+----------+-------------+------------------+

我已經試過

SELECT * 
FROM Items a 
JOIN Type t ON t.FK_Items = a.PK_Items 
WHERE t.Tag_txt = 'Slow';

其中給出（基本上）是什麼它應該給，但是當使用「慢」和「搖滾」我得到一張空的桌。

SELECT * 
FROM Items a 
JOIN Type t ON t.FK_Items = a.PK_Items 
WHERE t.Tag_txt = 'Slow' AND t.Tag_txt = 'Rock';

請幫助

來源

2014-06-27 LamKat

您可以使用having條款做到這一點。這裏有一種方法：

SELECT i.* 
FROM Items i JOIN 
    Type t 
    ON t.FK_Items = i.PK_Items 
WHERE t.Tag_txt IN *'Slow', 'Rock') 
GROUP BY i.PK_Items 
HAVING COUNT(DISTINCT t.tag_txt) = 2;

來源

2014-06-27 15:49:09

基於MySQL標籤的系統

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