凡在Sequelize ORM條件連接表

Question

我想這樣的查詢與sequ​​elize ORM：

SELECT "A".*,  
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id" 
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id" 
WHERE ("B"."userId" = '100' 
     OR "C"."userId" = '100') 

的問題是，sequelise不是讓我來引用where子句中的「B」或「C」表。下面的代碼

A.findAll({ 
    include: [{ 
     model: B, 
     where: { 
      userId: 100 
     }, 
     required: false 

    }, { 
     model: C, 
     where: { 
      userId: 100 
     }, 
     required: false 
    }] 
] 

給我

SELECT "A".*,  
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id" AND "B"."userId" = 100 
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id" AND "C"."userId" = 100 

這是完全不同的查詢，以及

A.findAll({ 
    where: { 
     $or: [ 
      {'"B"."userId"' : 100}, 
      {'"C"."userId"' : 100} 
     ] 
    }, 
    include: [{ 
     model: B, 
     required: false 

    }, { 
     model: C, 
     required: false 
    }] 
] 

結果是否定甚至一個有效的查詢：

SELECT "A".*,  
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id" 
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id" 
WHERE ("A"."B.userId" = '100' 
     OR "A"."C.userId" = '100') 

是第一查詢甚至可能與sequ​​eliz e，還是我應該堅持原始查詢？ `：

Answer 1

裹在$$

A.findAll({ 
    where: { 
     $or: [ 
      {'$B.userId$' : 100}, 
      {'$C.userId$' : 100} 
     ] 
    }, 
    include: [{ 
     model: B, 
     required: false 

    }, { 
     model: C, 
     required: false 
    }] 
});