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我試圖創建一個頁面,檢查它是否正確登錄信息。出於某種原因,當我回應從數據庫選擇數據的結果查詢時,我沒有從數據庫中獲取數據,我不確定它是什麼數據。下面是顯示在頁面上:PHP/MySQL查詢返回不在數據庫中的結果
Connected successfully
Resource id #3
這裏是我的PHP代碼:
<?php
//start session
session_start();
//connect to MySQL Database
$con = mysql_connect('localhost', 'root', '');
if (!$con) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully<br />';
// make members the current db
$db_selected = mysql_select_db('members_db', $con);
if (!$db_selected) {
die ('Can\'t use members database : ' . mysql_error());
}
$email = $_SESSION['email'];
$result = mysql_query("SELECT email,password FROM `members` WHERE 'email' = '$email'");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
if ($email == $row[0] && $_SESSION['password'] == $row[1])
{
$_SESSION['loggedin']="YES";
$url= "Location: welcome.php";
header($url);
exit;
}
echo $result;
/*
//Problems:
$problem = "";
if ($email == $row[0] && $_SESSION['password'] != $row[1])
{
$problem = "invalidPassword";
}
if ($email != $row[0])
{
$problem = "InvalidUser";
}
$url = "Location: index.php?problem=$problem";
header($url);
exit;*/
?>
mysql_query返回一個資源,所以這就是您在回顯時獲得的資源。你應該看看'$ row'中的內容,它會告訴你爲什麼你的失敗 –
必須使用'mysql'是折舊使用'mysqli' – Chitowns24
嘗試'echo $ row [0]; $ row = mysql_fetch_row($ result);'後的echo $ row [1]''。還要確保你的查詢返回一行。您可以使用['mysql_num_rows'](http://php.net/manual/en/function.mysql-num-rows.php)查找返回的行數。 – Uours