我們在使用Java MimeMessage發送電子郵件時手動設置自定義Message-ID標頭。 Message-ID格式遵循RFC822標準。但是,在通過Gmail API發送郵件時,Message-ID頭將被gmail中的新郵件覆蓋。Gmail API在發送電子郵件時覆蓋自定義Message-ID標頭
相反,如果我們我們通過SMTP發送郵件並通過SMTP發送電子郵件,則自定義郵件ID將由Gmail保留。
有沒有辦法在通過Gmail API發送電子郵件時擁有自定義消息ID?
我檢查了以下問題,但我不確定它是否仍然如此。 (RFC822 Message-Id in new Gmail API)
[UPDATE]
EmailMimeMessage.scala
package utils.email
import javax.mail._
import javax.mail.internet._
import play.api.Logger
class EmailMimeMessage(session: Session, messageId: String) extends MimeMessage(session) {
@throws(classOf[MessagingException])
override def updateMessageID(): Unit = {
Logger.info(s"[EmailMimeMessage] before sending add message id: $messageId")
setHeader("Message-ID", messageId)
}
}
GmailApiService.scala
package utils.email
import java.io.ByteArrayOutputStream
import java.util.Properties
import javax.mail.Session
import javax.mail.internet.{InternetAddress, MimeMessage}
import com.google.api.client.auth.oauth2.{BearerToken, Credential}
import com.google.api.client.googleapis.javanet.GoogleNetHttpTransport
import com.google.api.client.http.HttpTransport
import com.google.api.client.json.JsonFactory
import com.google.api.client.json.jackson2.JacksonFactory
import com.google.api.client.repackaged.org.apache.commons.codec.binary.Base64
import com.google.api.services.gmail.Gmail
import scala.util.Try
case class EmailToBeSent(
to_email: String,
from_email: String,
from_name: String,
reply_to_email: String,
subject: String,
textBody: String,
htmlBody: String,
message_id: String
)
object GmailApiService {
private val APPLICATION_NAME: String = "Gmail API Java Quickstart"
private val JSON_FACTORY: JsonFactory = JacksonFactory.getDefaultInstance
private val HTTP_TRANSPORT: HttpTransport = GoogleNetHttpTransport.newTrustedTransport()
def createEmail(emailToBeSent: EmailToBeSent): Try[MimeMessage] = Try {
val props = new Properties()
val session = Session.getDefaultInstance(props, null)
val email = new EmailMimeMessage(session, emailToBeSent.message_id)
email.setFrom(new InternetAddress(emailToBeSent.from_email))
email.addRecipient(javax.mail.Message.RecipientType.TO, new InternetAddress(emailToBeSent.to_email))
email.setSubject(emailToBeSent.subject)
email.setText(emailToBeSent.textBody)
email
}
def createMessageWithEmail(email: MimeMessage) = Try {
val baos = new ByteArrayOutputStream
email.writeTo(baos)
val encodedEmail = Base64.encodeBase64URLSafeString(baos.toByteArray)
val message = new com.google.api.services.gmail.model.Message()
message.setRaw(encodedEmail)
message
}
def sendGmailService(emailToBeSent: EmailToBeSent, accessToken: String) = Try {
val credential = new Credential(BearerToken.authorizationHeaderAccessMethod)
.setAccessToken(accessToken)
val service = new Gmail.Builder(HTTP_TRANSPORT, JSON_FACTORY, credential).setApplicationName(APPLICATION_NAME).build
val user = "me"
val message = createEmail(emailToBeSent) flatMap { email => createMessageWithEmail(email) }
val sentMessage = service.users().messages().send(user, message.get).execute()
sentMessage
}
}
在調用GmailApiService.sendGmailService作爲(與Message-ID如下:「< 1495728783999.123 .456.local @ examplegmail.com>「),在發送的電子郵件中,Message-ID被GMail覆蓋,例如」YYfdasCA [email protected]「:
val emailToBeSent = EmailToBeSent(
to_email = "[email protected]",
from_email = "[email protected]",
from_name = "John Doe",
reply_to_email = "[email protected]",
subject = "How are you ?",
textBody = "Hey, how are you ?",
htmlBody = "<strong>Hey, how are you ?</strong>",
message_id ="<[email protected]>",
in_reply_to_id = None,
sender_email_settings_id = 0
)
val sentMsg = GmailApiService.sendGmailService(emailToBeSent, GOOGLE_OAUTH_ACCESS_TOKEN).get
尋求調試幫助的問題(「爲什麼這個代碼不工作?」)必須包含所需的行爲,特定的問題或錯誤以及在問題本身中重現問題所需的最短代碼。沒有明確問題陳述的問題對其他讀者無益。請參閱:如何創建最小,完整和可驗證示例。 – DaImTo
@DaImTo謝謝您,添加了我用來測試發送電子郵件的代碼,以及一個示例 –