在foreach循環中運行第二個查詢？

Question

需要在foreach中運行2個查詢，但不能沒有錯誤地執行。

所以，我有這個用於顯示評論：

$query = 'SELECT * FROM comments WHERE updatepostid = "' . $postID . '"'; 
    try { 
     $stmt = $db->prepare($query); 
     $stmt->execute(); 
     $countcomments = $stmt->rowCount(); 
     } 
     catch (PDOException $ex) 
     { 
      die("Failed to run query: " . $ex->getMessage()); 
     } 

$rows = $stmt->fetchAll(); 
foreach ($rows as $row): 
$commentID  = $row['commentID']; 
$usercommentID = $row['userID']; 
$commentusername = ucfirst($row['commentusername']); 
$comment   = ucfirst($row['comment']); 
$updatepostid = $row['updatepostid']; 

<div class="textcomment"> 
    <?php 
     echo "<a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment"; 
    ?> 
</div> 


<?php endforeach; ?> 

然後我不過想要運行的用戶數據庫的另一個查詢檢查什麼權限的用戶擁有，然後類的評論用戶名設置爲類。

該查詢將是例如

<?php 

$query2 = 'SELECT * FROM users WHERE id = "' . $usercommentID . '"'; 
    try { 
     $stmt = $db->prepare($query2); 
     $stmt->execute(); 
     } 
     catch (PDOException $ex) 
     { 
      die("Failed to run query: " . $ex->getMessage()); 
     } 

$rows = $stmt->fetchAll(); 
foreach ($rows as $row): 
$rights = $row['rights']; 

if ($rights = '1') { 
    $rightscommentcolor = 'userrights1'; 
} else if ($rights = '5') { 
    $rightscommentcolor = 'userrights5'; 
} 

?> 
<?php endforeach; ?> 

這是怎麼回事？

P.S.我明白上面的代碼可能會讓人哭泣。

Answer 1

您可以加入選擇的表提到：

<?php 

$query = "SELECT * FROM comments c 
      JOIN users u ON u.usercommentID = c.userID 
      WHERE updatepostid = :updatepostid"; 
    try { 
     $stmt = $db->prepare($query); 
     $stmt->execute(); 
     $countcomments = $stmt->rowCount(); 
     } 
     catch (PDOException $ex) 
     { 
      die("Failed to run query: " . $ex->getMessage()); 
     } 

$rows = $stmt->fetchAll(); 
foreach ($rows as $row): 

$commentID  = $row['commentID']; 
$usercommentID = $row['userID']; 
$commentusername = ucfirst($row['commentusername']); 
$comment   = ucfirst($row['comment']); 
$updatepostid = $row['updatepostid']; 

if ($rights = '1') { 
    $rightscommentcolor = 'userrights1'; 
} else if ($rights = '5') { 
    $rightscommentcolor = 'userrights5'; 
} 

echo "<div class="textcomment"><a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment</div>"; 

endforeach; 

?> 

你也可以內第一插入第二個循環，並分配不同的變量到第二個循環，使其不與衝突首先如下，但加盟將是一個更好的選擇：

<?php 

$query = 'SELECT * FROM comments WHERE updatepostid = "' . $postID . '"'; 
    try { 
     $stmt = $db->prepare($query); 
     $stmt->execute(); 
     $countcomments = $stmt->rowCount(); 
     } 
     catch (PDOException $ex) 
     { 
      die("Failed to run query: " . $ex->getMessage()); 
     } 

$rows = $stmt->fetchAll(); 
foreach ($rows as $row): 

$commentID  = $row['commentID']; 
$usercommentID = $row['userID']; 
$commentusername = ucfirst($row['commentusername']); 
$comment   = ucfirst($row['comment']); 
$updatepostid = $row['updatepostid']; 

$query2 = 'SELECT * FROM users WHERE usercommentID = "' . $usercommentID . '"'; 
    try { 
     $stmt2 = $db->prepare($query2); 
     $stmt2->execute(); 
     } 
     catch (PDOException $ex2) 
     { 
      die("Failed to run query: " . $ex2->getMessage()); 
     } 

$rows2 = $stmt2->fetchAll(); 
foreach ($rows2 as $row2): 
$rights = $row2['rights']; 

if ($rights = '1') { 
    $rightscommentcolor = 'userrights1'; 
} else if ($rights = '5') { 
    $rightscommentcolor = 'userrights5'; 
} 

endforeach; 

echo "<div class="textcomment"><a class='$rightscommentcolor'>$commentusername:</a>&nbsp; $comment</div>"; 

endforeach; 

?> 

Answer 2

對連接使用單個查詢。另外，由於您使用的是PDO，因此您應該使用參數化查詢而不是串聯字符串。

$query = "SELECT * FROM comments c 
      JOIN users u ON u.id = c.userID 
      WHERE updatepostid = :updatepostid"; 
try { 
    $stmt = $db->prepare($query); 
    $stmt->execute(array(':updatepostid' => $postID)); 
    } 
catch (PDOException $ex) 
    { 
     die("Failed to run query: " . $ex->getMessage()); 
    }