正確使用Interbase子查詢中的別名

Question

我的新創建的別名ABONO和CARGO存在問題。 ALIASES（用於結果的列名）和SQL查詢正常工作直到我嘗試計算「ABONO-CARGO AS AJUSTE」=> Interbase給出了一個錯誤，它不知道列「ABONO」。

動態SQL錯誤 SQL錯誤代碼= -206 列未知 ABONO

有什麼不對？

SELECT M."MOV_CUENTA", 
     (SELECT SUM(MM."MOV_MONTO") 
      FROM "movimientos" MM 
     WHERE MM."MOV_TIPOMOV" = 'A' AND MM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY MM."MOV_CUENTA" 
     ) AS ABONO, 
     (SELECT SUM(XM."MOV_MONTO") 
      FROM "movimientos" XM 
     WHERE XM."MOV_TIPOMOV" = 'C' AND XM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY XM."MOV_CUENTA" 
     ) AS CARGO, 
     ABONO-CARGO AS AJUSTE 
    FROM "cuentasSaldo" CS 
INNER JOIN "movimientos" M ON (CS."ID_CUENTAMUN" = M."MOV_CUENTA") 
INNER JOIN "ajustes" AA ON (M."ID_AJUSTE" = AA."ID_AJUSTE") 
INNER JOIN "documentos" DD ON (AA."ID_DOCUMENTO" = DD."ID_DOCUMENTO") 
WHERE M."ID_AJUSTE" IN 
      (SELECT A."ID_AJUSTE" 
       FROM "ajustes" A 
      WHERE A."ID_DOCUMENTO" IN 
        (SELECT D."ID_DOCUMENTO" 
         FROM "documentos" D 
         WHERE D."ID_EMPRESA" = 1 AND D."DOC_EDITABLE" = 1 
        ) 
      ) 
ORDER BY M."ID_AJUSTE", M."MOV_CUENTA" 

Answer 1

簡潔地說，在許多SQL數據庫管理系統，在選擇列表中給出的列別名不能用在別處查詢中使用，甚至在選擇列表中的其他部分。

您將不得不在報告工具中進行計算，或者重複兩次查詢以獲取該值（這很痛苦，即使使用copy'n'paste —也只是一個理由，報告工具）。

SELECT M."MOV_CUENTA", 
     (SELECT SUM(MM."MOV_MONTO") 
      FROM "movimientos" MM 
     WHERE MM."MOV_TIPOMOV" = 'A' AND MM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY MM."MOV_CUENTA" 
     ) AS ABONO, 
     (SELECT SUM(XM."MOV_MONTO") 
      FROM "movimientos" XM 
     WHERE XM."MOV_TIPOMOV" = 'C' AND XM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY XM."MOV_CUENTA" 
     ) AS CARGO, 
     ((SELECT SUM(MM."MOV_MONTO") 
      FROM "movimientos" MM 
     WHERE MM."MOV_TIPOMOV" = 'A' AND MM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY MM."MOV_CUENTA" 
     ) - 
     (SELECT SUM(XM."MOV_MONTO") 
      FROM "movimientos" XM 
     WHERE XM."MOV_TIPOMOV" = 'C' AND XM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
     GROUP BY XM."MOV_CUENTA" 
     )) AS AJUSTE 
    FROM "cuentasSaldo" CS 
INNER JOIN "movimientos" M ON (CS."ID_CUENTAMUN" = M."MOV_CUENTA") 
INNER JOIN "ajustes" AA ON (M."ID_AJUSTE" = AA."ID_AJUSTE") 
INNER JOIN "documentos" DD ON (AA."ID_DOCUMENTO" = DD."ID_DOCUMENTO") 
WHERE M."ID_AJUSTE" IN 
      (SELECT A."ID_AJUSTE" 
       FROM "ajustes" A 
      WHERE A."ID_DOCUMENTO" IN 
        (SELECT D."ID_DOCUMENTO" 
         FROM "documentos" D 
         WHERE D."ID_EMPRESA" = 1 AND D."DOC_EDITABLE" = 1 
        ) 
      ) 
ORDER BY M."ID_AJUSTE", M."MOV_CUENTA" 

在這些表達式中很容易失去孤獨的-。

另一種方式來做到這一點是：

SELECT "MOV_CUENTA", ABONO, CARGO, (ABONO - CARGO) AS AJUSTE 
    FROM (SELECT M."ID_AJUSTE", 
       M."MOV_CUENTA", 
       (SELECT SUM(MM."MOV_MONTO") 
        FROM "movimientos" MM 
       WHERE MM."MOV_TIPOMOV" = 'A' AND MM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
       GROUP BY MM."MOV_CUENTA" 
       ) AS ABONO, 
       (SELECT SUM(XM."MOV_MONTO") 
        FROM "movimientos" XM 
       WHERE XM."MOV_TIPOMOV" = 'C' AND XM."MOV_CUENTA" = CS."ID_CUENTAMUN" 
       GROUP BY XM."MOV_CUENTA" 
       ) AS CARGO 
      FROM "cuentasSaldo" CS 
     INNER JOIN "movimientos" M ON (CS."ID_CUENTAMUN" = M."MOV_CUENTA") 
     INNER JOIN "ajustes" AA ON (M."ID_AJUSTE" = AA."ID_AJUSTE") 
     INNER JOIN "documentos" DD ON (AA."ID_DOCUMENTO" = DD."ID_DOCUMENTO") 
     WHERE M."ID_AJUSTE" IN 
        (SELECT A."ID_AJUSTE" 
         FROM "ajustes" A 
        WHERE A."ID_DOCUMENTO" IN 
          (SELECT D."ID_DOCUMENTO" 
           FROM "documentos" D 
           WHERE D."ID_EMPRESA" = 1 AND D."DOC_EDITABLE" = 1 
          ) 
        ) 
     ) AS X 
ORDER BY "ID_AJUSTE", "MOV_CUENTA" 

我想你也應該被選擇ID_AJUSTE，但是這是你的決定。我不確定你是否真的需要所有這些分隔標識符，但我基本上沒有將它們保留下來。

Answer 2

你應該在表「cuentasSaldo」（CS）中有一個字段ABONO，並且你有一個子查詢別名爲ABONO。所以你有兩個同名的「對象」。 我建議你嘗試在格式中調用字段：query.field。 行6中的示例： 而不是：ABONO-CARGO AS AJUSTE 使用：CS.ABONO-CARGO AS AJUSTE。