我試圖做一個鏈接的選擇菜單,我有這個模型:新手Django的智能/鏈接菜單的麻煩
from django.db import models
class Health_plan(models.Model):
name = models.CharField(max_length=15)
class Doctors_list(models.Model):
name = models.CharField(max_length=30)
specialty = models.CharField(max_length=15)
health_plans = models.ManyToManyField(Health_plan, related_name="doctors")
location = models.CharField(max_length=15)
def __unicode__(self):
return self.name
這是我forms.py
:
class SpecForm(ModelForm):
a = Doctors_list.objects.values_list('specialty', flat=True)
unique = [('---------------','---------------')] + [(i,i) for i in set(a)]
specialty = forms.ChoiceField(choices=unique)
class Meta:
model = Doctors_list
class HealthForm(ModelForm):
hplan = ChainedForeignKey(
Health_plan,
chained_field="specialty",
chained_model_field="specialty",
show_all=False,
auto_choose=True
)
我urls.py
:
from django.conf.urls import patterns, include, url
from testApp.views import spec_form
from testApp.views import health_form
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
url(r'^$', 'Medbook.views.home', name='home'),
# url(r'^Medbook/', include('Medbook.foo.urls')),
url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
url(r'^admin/', include(admin.site.urls)),
url(r'^hello/$', spec_form),
url(r'^hello/$', health_form),
)
and my views.py
:
from django.shortcuts import render_to_response
from testApp.forms import SpecForm
from testApp.forms import HealthForm
def spec_form (request):
if request.method == 'POST':
form = SpecForm(request.POST)
if form.is_valid():
form.save()
else:
form = SpecForm()
return render_to_response('hello.html', {'form':form})
def health_form (request):
if request.method == 'POST':
form = HealthForm(request.POST)
if form.is_valid():
form.save()
else:
form = SpecForm()
return render_to_response('hello.html', {'form':form})
我是Django的新手,我覺得這很棘手。用戶必須選擇一個專業,然後出現涵蓋該專業的health_plans。
health_plans與醫生有許多關係。當一個人選擇一個專業時,腳本應該檢查哪個醫生屬於該專業,並檢索這些醫生持有的所有健康計劃。
到目前爲止,我在菜單中唯一得到的是:Health_plan object Health_plan object Health_plan object
我希望我清楚,我的代碼,它不是。
任何幫助,懇請讚賞
任何提示?具體文檔閱讀? – ClaudioA 2013-05-08 20:07:08