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我遇到了一種情況,我想在正則表達式中使用非貪婪原子.*?
。非貪婪正則表達式基於正則表達式中的原子位置貪婪
set input "Device ID: HOST1
Interface: GigabitEthernet0/1, Port ID (outgoing port): GigabitEthernet2/43
Device ID: HOST2
Entry address(es):
Interface: GigabitEthernet0/2, Port ID (outgoing port): GigabitEthernet2/43
"
puts "======== Non-Greedy regex starting with some other patterns ========"
puts [ regexp -inline {Device\s+ID:.*?outgoing\s+port\):\s+} $input]
puts "======== Non-Greedy regex at first ========"
puts [ regexp -inline {.*?outgoing\s+port\):\s+} $input]
輸出:
======== Non-Greedy regex starting with some other patterns ========
{Device ID: HOST1
Interface: GigabitEthernet0/1, Port ID (outgoing port): GigabitEthernet2/43
Device ID: HOST2
Entry address(es):
Interface: GigabitEthernet0/2, Port ID (outgoing port): }
======== Non-Greedy regex at first ========
{Device ID: HOST1
Interface: GigabitEthernet0/1, Port ID (outgoing port): }
.*?outgoing\s+port\):\s+
雖然是匹配直到第一次出現,所述圖案Device\s+ID:.*?outgoing\s+port\):\s+
不是在比賽的第一個發生停止。
爲什麼非貪心匹配的行爲會因爲放置原子而受到影響?
呵呵,很好的回答,在回答時重新閱讀它的記憶,但沒有發現第一個操作符在'Device \ s + ...'中貪婪。所以如果我做得好,把第一個'\ s +'改成'\ s +?'應該做什麼? – Tensibai
@Tensibai&@glenn:是的!使用'Device \ s +?ID:。*?outgoing \ s + port \':\ s +'它只匹配到第一個匹配項。這很棒。感謝格倫先生! – Dinesh