2017-07-22 154 views
0

我一直在創建一個組合計算器,這是我很難創建的東西。我經常試圖解決的問題是處理我的代碼中的任何無限循環。程序一直運行 - 無限循環

oglist = ["a","b","c","d"] 
combocounter = 3 
lists = {} 
comboloop = True 
combolist = ["lol"] 
pendinglist = ["lol"] 
for x in range(0, combocounter): 
    lists["list" + str(x)] = ["lol"] 
def loop(counter1): 
    global recursion1 
    global recursion2 
    if len(lists["list" + str(counter1)]) == 0: 
     lists["list" + str(counter1 - 1)] = lists["list" + str(counter1 - 1)][1:] 
     print(lists) 
     recursion1 = True 
     recursion2 = True 
    else: 
     lists["list" + str(counter1 + 1)] = lists["list" + str(counter1)][1:] 
     print(lists) 
     recursion2 = False 
    return 
def startingloop(): 
    global recursion1 
    if len(lists["list0"]) == 0: 
     comboloop = False 
    else: 
     lists["list1"] = lists["list0"][1:] 
     print(lists) 
     recursion1 = False 
    return 
def endingloop(): 
    global counter2 
    global recursion2 
    if len(lists["list2"]) == 0: 
     lists["list1"] = lists["list1"][1:] 
     print(lists) 
     recursion2 = True 
    else: 
     combolist[counter2] = lists["list0"][0] 
     for y in range(1, combocounter): 
      combolist[counter2] = combolist[counter2] + lists["list" + str(y)][0] 
     combolist.append("lol") 
     lists["list2"] = lists["list2"][1:] 
     counter2 += 1 
     print(lists) 
     print(combolist) 
    return 
lists["list0"] = oglist 
counter2 = 0 
while comboloop == True: 
    startingloop() 
    while recursion1 == False: 
     loop(1) 
     while recursion2 == False: 
      endingloop() 
combolist.remove("lol") 
print(combolist) 

我已經放在一大堆的打印功能: print(lists)print(combolist)。 當我運行它,列表和combolist不斷更新和打印。然後停止打印,但我的程序不斷運行。它也從來沒有達到

combolist.remove("lol") 
print(combolist) 

我經歷了努力遵循我的代碼的邏輯來發現任何問題,但我沒有。我的代碼中不斷循環着什麼?

回答

0

comboloop = False正在創建一個局部變量,它會影響您的全局調用comboloop。如果您在startingloop添加

global comboloop 

()函數,程序退出