您的JSON代表簡單的地圖列表,更確切地說:List<Map<String, List<String>>>
。您可以在此JSON轉換成該POJO:
class JsonEntity {
public List<Map<String, List<String>>> list;
public String kind;
public StuffList toStuffList() {
StuffList stuffList = createStuffListObject();
return stuffList;
}
private StuffList createStuffListObject() {
StuffList stuffList = new StuffList();
stuffList.kind = kind;
stuffList.list = createItemsList();
return stuffList;
}
private List<Stuff> createItemsList() {
List<Stuff> items = new ArrayList<Stuff>(list.size());
for (Map<String, List<String>> item : list) {
items.add(convertToStuff(item));
}
return items;
}
private Stuff convertToStuff(Map<String, List<String>> item) {
Stuff stuff = new Stuff();
stuff.name = item.keySet().iterator().next();
stuff.items = item.values().iterator().next();
return stuff;
}
}
現在我們可以用這種方式反序列化JSON:
public static void main(String[] args) throws Exception {
String json = "{\"list\":[{\"monday\":[\"apple\", \"bread\"]},{\"sunday\":[\"bacon\", \"beer\"]} ],\"kind\":\"shoplist\"}";
ObjectMapper objectMapper = new ObjectMapper();
JsonEntity jsonEntity = objectMapper.readValue(json, JsonEntity.class);
System.out.println(jsonEntity.toStuffList());
}
輸出的程序:
list=[[name=monday, items=[apple, bread]], [name=sunday, items=[bacon, beer]]], kind=shoplist
有這樣的一個例子[傑克遜教程](http://wiki.fasterxml.com/JacksonInFiveMinutes) –
編輯的問題,使其更清晰 –
無論如何,沒有發現如何做到這一點在教程 –