SQL從一列中取頂部和底部元素，並將它們放在兩個不同的列中

Question

我有2個select語句。我想按照字母順序排列第一個名字，並將其放在名爲First的列中，並在名爲Last的字段中按字母順序放在姓氏的旁邊。

SELECT Name AS 'First' 
FROM contactlist 
ORDER BY Name ASC 
LIMIT 1; 

SELECT Name AS 'Last' 
FROM contactlist 
ORDER BY Name DESC 
LIMIT 1; 

Answer 1

不知道爲什麼你需要這一點，但在這裏你去：

SELECT First, Last 
FROM (
    SELECT Name AS 'First' 
    FROM contactlist 
    ORDER BY Name ASC 
    LIMIT 1 
) t, (
    SELECT Name AS 'Last' 
    FROM contactlist 
    ORDER BY Name DESC 
    LIMIT 1 
) t2 

可能會多一點樂趣，採取一切你的名字和行號（第一ASC到DESC姓）與它們匹配 - 這樣的事情：

SELECT First, Last 
FROM (
    SELECT Name AS 'First', 
    @rowNum:=@rowNum + 1 rn 
    FROM contactlist 
    JOIN (SELECT @rowNum:= 0) r 
    ORDER BY Name ASC 
) t JOIN 
(
    SELECT Name AS 'Last', 
    @rowNum2:=@rowNum2 + 1 rn 
    FROM contactlist 
    JOIN (SELECT @rowNum2:= 0) r 
    ORDER BY Name DESC 
) t2 ON t.rn = t2.rn 

和一些Fiddle。