使用sql存儲過程生成字母數字序列

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我需要使用主鍵自動生成員工參考號唯一序列。樣品Personal Data個人紀錄：（A0001-Z9999）現在exeeded最大計數（Z9999）下一個序列我要生成：使用sql存儲過程生成字母數字序列

AA001-AA999, 
AB001-AB999, 
AZ999-BA001 
BC001-BZ999, 
CA001-CZ999, 
ZA001-ZZ999..LIKE THIS..IN sql server stored procedure.. 

...ZZ999 LIKE THIS

來源

2016-05-13 Rino Mathew

它是你的家庭作品，我們需要做什麼或什麼？你到目前爲止所嘗試過的？發佈 – mohan111

你可以不喜歡這樣。

首先創建一個序列來生成整數的序列號從1

CREATE SEQUENCE dbo.MySeq AS INT 
    START WITH 1 
    INCREMENT BY 1;

開始然後創建，其產生所需的格式的序列碼的存儲過程。

CREATE PROCEDURE dbo.up_GetNextSequence 
(
    @seq nchar(5) out 
) 
AS 
DECLARE @i int = NEXT VALUE FOR dbo.MySeq; 

IF @i > 685323 
BEGIN 
    RAISERROR(N'Sequence is out of range.', 16, 0); 
END 

IF @i < 10000 
BEGIN 
    SET @seq = N'A' + FORMAT(@i, 'D4'); 
END 
ELSE 
BEGIN 
    DECLARE @j int; 
    SET @j = @i - 9999; 

    DECLARE @k int; 
    SET @k = ((@j - 1) % 999) + 1; 

    DECLARE @l int; 
    SET @l = (@j - 1)/999; 

    DECLARE @m int; 
    SET @m = (@l % 26) + 65; 

    DECLARE @n int; 
    SET @n = (@l/26) + 65; 

    SET @seq = NCHAR(@n) + NCHAR(@m) + FORMAT(@k, 'D3'); 
END;

然後測試存儲過程。

DECLARE @seq nchar(5); 
EXEC up_GetNextSequence @seq output; 
SELECT @seq AS '@seq'

說它四次，我們得到了爲「A0005」。

爲了測試第一斷點，改變序列對象，以便它返回9999。然後再次執行測試代碼。

ALTER SEQUENCE dbo.MySeq 
    RESTART WITH 9999;

等等......

ALTER SEQUENCE dbo.MySeq 
    RESTART WITH 10998;

ALTER SEQUENCE dbo.MySeq 
    RESTART WITH 35973;

ALTER SEQUENCE dbo.MySeq 
    RESTART WITH 659349;

測試當它到達允許範圍的末尾時會發生什麼。

ALTER SEQUENCE dbo.MySeq 
    RESTART WITH 685323;

執行存儲過程一個更多的時間和它產生一個錯誤，稱序列超出範圍。這是設計。

來源

2016-05-13 08:59:00 RichardCL

該查詢會給你所有的值，你需要：

--here we take all the english alphabet 
;WITH chars AS (
SELECT CHAR(65) as chars, 65 as [level] 
UNION ALL 
SELECT CHAR([level]+1), [level]+1 
FROM chars 
WHERE [level]-65 < 25 
), cte AS (-- Here we take didits from 1 to 999 
SELECT 1 as digits 
UNION ALL 
SELECT digits+1 
FROM cte 
WHERE digits < 999 
), codes AS (-- here we get all chars combinations "AA", "AB" etc 
SELECT c1.chars+c2.chars as code 
FROM chars c1 
cross join chars c2 
) 

--And here come cortesian join to get all refnomes ou need 
SELECT code + CASE WHEN LEN(digits) = 1 THEN CONCAT('00',cast(digits as nvarchar(1))) 
      WHEN LEN(digits) = 2 THEN CONCAT('0',cast(digits as nvarchar(2))) 
      ELSE cast(digits as nvarchar(3)) END as Refno 
FROM cte 
CROSS JOIN codes 
ORDER BY code 
OPTION (maxrecursion 1000)

輸出：

Refno 
AA001 
AA002 
AA003 
AA004 
AA005 
AA006 
AA007 
AA008 
AA009 
AA010 
AA011 
AA012 
AA013 
AA014 
AA015 
AA016 
AA017 
... 
etc 
ZZ999

〜675324行

你可以把結果到一些表以及您在該表中需要的存儲過程返回值。

來源

2016-05-13 10:21:48 gofr1

使用sql存儲過程生成字母數字序列

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