2011-11-13 98 views
2

比方說,我有一個叫人與列的表:遞歸查詢列

id, name, parent_id 

,讓我們說我有一些像這樣的數據:

1, Bob, null 
2, Mary, 1 
3, Tim, 1 
4, Sally, 3 

所以鮑勃有兩個孩子:瑪麗和蒂姆。 和蒂姆有1個孩子:莎莉(祖父母是鮑勃)

什麼是寫一個JPA查詢的最簡單方法,以便我可以找到鮑勃的所有後代? (即結果將返回瑪麗,蒂姆和莎莉)

回答

3

我不認爲你可以用普通的JPA做到這一點。

但是,如果你可以修改你的表像這樣

id, name, parent_path(string) 

您的信息就會看起來像這樣

1, Bob, null 
2, Mary, 1 
3, Tim, 1 
4, Sally, 1/3 
5, John, 1/3/4 
6, Huge, 1/3/4/5 

,那麼你可以查詢使用類似條款的所有後代。 例如:

select p from Person p where p.parentPath like '1/%' 

這裏1 - 是parentPath + ENTITYID,所以對於鮑勃喜歡條款看起來像

like '1/%' 

因爲Bob的parentPath爲空和Bob的ID爲1

而對於Sally的查詢將如下所示

select p from Person p where p.parentPath like '1/3/4/%' 

因爲Sally的parentPath是「1/3」和Sally的id是4

,如果你要添加一個新的孩子,你只需要它的設置PARENT_PATH到

parent.parentPath + '/' + parent.id 
+1

路徑的想法一般都很好,但你需要小心「like」; 「像'1/3/4%'這樣的parentPath會拿起'1/3/42'以及'1/3/4/2'。通常我通過做'1/3/4 /%'。 – wrschneider

+0

感謝您關注此事。 – szhem

2

大多數現代DBMS支持使用遞歸公用表表達式層次查詢。如果你可以通過一個簡單的SQL語句的JPA層,這可以很容易地類似於以下一條語句完成:

WITH RECURSIVE people_tree (id, name, parent) as 
(
    SELECT id, name, parent_id 
    FROM people 
    WHERE parent name = 'Bob' 

    UNION ALL 

    SELECT p2.id, p2.name, p2.parent_id 
    FROM people p2 
    INNER JOIN people_tree ON people_tree.id = p2.parent_id 
) 
SELECT * 
FROM people_tree 
ORDER BY name; 
0

在SQL Server 2008中的以下查詢的工作來獲取級別的每個元素是,假設你的表名爲Hierarchical_Test1,幷包含字段「ID,姓名,PARENT_ID」:

with family_tree (parent_id, id, name, level) AS 
(
-- Anchor member definition 
select f.parent_id, f.id, f.name, 0 as level 
from dbo.Hierarchical_Test1 f 
where f.parent_id=0 
union all 
-- Recursive member definition 
select f2.parent_id, f2.id, f2.name, level + 1 
from dbo.Hierarchical_Test1 as f2 
inner join family_tree as f3 
on f2.parent_id = f3.id 
) 
-- Statement that executes the CTE 
select parent_id, id, name, level 
from family_tree 

而這一次得到你所有的元素的祖先:

with family_tree (parent_id, id, name, level, parent_path) AS 
(
-- Anchor member definition 
select f.parent_id, f.id, f.name, 0 as level, 
      CAST('/' as varchar(255)) as parent_path 
from dbo.Hierarchical_Test1 f 
where f.parent_id=0 
union all 
-- Recursive member definition 
select f2.parent_id, f2.id, f2.name, level + 1, 
      CAST(
       CAST('/' as varchar(255)) 
       + CAST(f2.parent_id as varchar(255)) 
       + CAST(f3.parent_path as varchar(255)) 
      as varchar(255)) 
from dbo.Hierarchical_Test1 as f2 
inner join family_tree as f3 
on f2.parent_id = f3.id 
) 
-- Statement that executes the CTE 
select parent_id, id, name, level, parent_path 
from family_tree